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Three boxes of lengths 60m,30m and 45m are to be cut into pieces of equal length. What is the greatest possible length of each pieces ?
- a)15m
- b)18m
- c)5m
- d)3m
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Three boxes of lengths 60m,30m and 45m are to be cut into pieces of eq...
Explanation:
- To find the greatest possible length of each piece, we need to find the greatest common divisor (GCD) of the lengths of the boxes.
- The lengths of the boxes are 60m, 30m, and 45m.
- We can find the GCD of these lengths by finding the GCD of the pairwise combinations of the lengths.
- GCD(60,30) = 30
- GCD(30,45) = 15
- GCD(60,45) = 15
- Therefore, the greatest common divisor of 60, 30, and 45 is 15m.
- So, the greatest possible length of each piece that can be cut from the boxes is 15m.
Therefore, the correct answer is option A) 15m.
- To find the greatest possible length of each piece, we need to find the greatest common divisor (GCD) of the lengths of the boxes.
- The lengths of the boxes are 60m, 30m, and 45m.
- We can find the GCD of these lengths by finding the GCD of the pairwise combinations of the lengths.
- GCD(60,30) = 30
- GCD(30,45) = 15
- GCD(60,45) = 15
- Therefore, the greatest common divisor of 60, 30, and 45 is 15m.
- So, the greatest possible length of each piece that can be cut from the boxes is 15m.
Therefore, the correct answer is option A) 15m.
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Three boxes of lengths 60m,30m and 45m are to be cut into pieces of eq...
HCF of 60, 30 and 45m = 15m
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Three boxes of lengths 60m,30m and 45m are to be cut into pieces of equal length. What is the greatest possible length of each pieces ?a)15mb)18mc)5md)3me)None of theseCorrect answer is option 'A'. Can you explain this answer?
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