A circular wire of radius 56 cm is cut and bent in the form of a recta...
The perimeter of the circle, that is, the rectangle is,
P=2πr = 2 * 22/7 * 56 =16×22 cm.
Let us assume the actual length and breadth of the rectangle be, 6xand 5x
So perimeter will be,
P=2(6x+5x)=22x
16×22=22x
X=16.
The smaller side or breadth =5x=80cm
A circular wire of radius 56 cm is cut and bent in the form of a recta...
Given:
Radius of the circular wire = 56 cm
Ratio of sides of the rectangle = 6:5
We need to find the length of the smaller side of the rectangle.
Concept:
When a circular wire is cut and bent in the form of a rectangle, the perimeter of the rectangle is equal to the circumference of the circle.
Let's solve this step by step:
1. Circumference of the circle:
The circumference of a circle is given by the formula:
C = 2πr
Given that the radius of the circular wire is 56 cm, we can calculate the circumference:
C = 2π(56)
C = 112π cm
2. Perimeter of the rectangle:
The perimeter of a rectangle is given by the formula:
P = 2(l + b)
Let the length of the rectangle be 6x.
Then, the breadth of the rectangle will be 5x.
So, the perimeter of the rectangle is:
P = 2(6x + 5x)
P = 2(11x)
P = 22x
Since the perimeter of the rectangle is equal to the circumference of the circle, we can equate these two values:
22x = 112π
3. Finding the value of x:
Dividing both sides of the equation by 22, we get:
x = (112π) / 22
x = 4π
4. Finding the length of the smaller side of the rectangle:
The length of the smaller side of the rectangle is 5x.
Substituting the value of x, we get:
Length = 5(4π)
Length = 20π
Approximating the value of π to 3.14, we get:
Length ≈ 20(3.14)
Length ≈ 62.8 cm
Therefore, the length of the smaller side of the rectangle is approximately 62.8 cm.
Since none of the given options match the calculated value, the correct answer is None of these.