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Given the bond energies of N ≡ N , H − H and N − H bonds as 941.5, 433 and 391 kJ mole-1 respectively, the enthalpy of reaction N2(g)+ 3H2g → 2NH3(g) isa)-93 kJb)102 kJc)90 kJd)-105 kJCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Given the bond energies of N ≡ N , H − H and N − H bonds as 941.5, 433 and 391 kJ mole-1 respectively, the enthalpy of reaction N2(g)+ 3H2g → 2NH3(g) isa)-93 kJb)102 kJc)90 kJd)-105 kJCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given the bond energies of N ≡ N , H − H and N − H bonds as 941.5, 433 and 391 kJ mole-1 respectively, the enthalpy of reaction N2(g)+ 3H2g → 2NH3(g) isa)-93 kJb)102 kJc)90 kJd)-105 kJCorrect answer is option 'D'. Can you explain this answer?.

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