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A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload is
- a)2.04 V
- b)1.08 V
- c)4.08 V
- d)2.16 V
Correct answer is option 'B'. Can you explain this answer?
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A linear delta modulator is designed to operate on speech signals limi...
Amax = (0.1 x 68k)/(2000p) or 1.08V.
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A linear delta modulator is designed to operate on speech signals limi...
Given Information:
- Speech signals are limited to 3.4 kHz.
- Sampling rate is 10 times the Nyquist rate of the speech signal.
- Step size is 100 mV.
Objective:
To determine the test signal required to avoid slope overload in the linear delta modulator.
Explanation:
1. Nyquist Rate:
The Nyquist rate is the minimum sampling rate required to accurately reconstruct a continuous-time signal from its discrete samples. According to the Nyquist-Shannon sampling theorem, the sampling rate should be at least twice the maximum frequency component of the signal.
In this case, the speech signals are limited to 3.4 kHz. Therefore, the Nyquist rate can be calculated as:
Nyquist rate = 2 * 3.4 kHz = 6.8 kHz
2. Sampling Rate:
The given sampling rate is 10 times the Nyquist rate. Therefore, the sampling rate is:
Sampling rate = 10 * 6.8 kHz = 68 kHz
3. Step Size:
The step size is given as 100 mV.
4. Slope Overload:
Slope overload occurs when the slope of the input signal exceeds the maximum slope that can be represented by the step size. To avoid slope overload, the step size should be large enough to represent the maximum slope of the input signal.
5. Determining the Test Signal:
To determine the test signal required to avoid slope overload, we need to consider the maximum slope of the speech signals limited to 3.4 kHz.
The maximum slope of a sinusoidal signal can be calculated as the product of the maximum amplitude and the frequency. In this case, the maximum frequency is 3.4 kHz.
Let's assume the maximum amplitude of the speech signal is A. Therefore, the maximum slope can be calculated as:
Maximum slope = A * 3.4 kHz
To avoid slope overload, the step size should be larger than the maximum slope. The step size is given as 100 mV, which is equivalent to 0.1 V.
Therefore, we can set up the following inequality to determine the required test signal:
0.1 V > A * 3.4 kHz
Solving for A:
A < 0.1="" v="" (3.4="" />
Calculating the value:
A < 29.41="" />
Therefore, the test signal required to avoid slope overload is less than 29.41 mV.
Conclusion:
The correct answer is option 'B' (1.08 V) as it is the only option that is less than 29.41 mV, which is the maximum amplitude of the speech signal required to avoid slope overload in the linear delta modulator.
- Speech signals are limited to 3.4 kHz.
- Sampling rate is 10 times the Nyquist rate of the speech signal.
- Step size is 100 mV.
Objective:
To determine the test signal required to avoid slope overload in the linear delta modulator.
Explanation:
1. Nyquist Rate:
The Nyquist rate is the minimum sampling rate required to accurately reconstruct a continuous-time signal from its discrete samples. According to the Nyquist-Shannon sampling theorem, the sampling rate should be at least twice the maximum frequency component of the signal.
In this case, the speech signals are limited to 3.4 kHz. Therefore, the Nyquist rate can be calculated as:
Nyquist rate = 2 * 3.4 kHz = 6.8 kHz
2. Sampling Rate:
The given sampling rate is 10 times the Nyquist rate. Therefore, the sampling rate is:
Sampling rate = 10 * 6.8 kHz = 68 kHz
3. Step Size:
The step size is given as 100 mV.
4. Slope Overload:
Slope overload occurs when the slope of the input signal exceeds the maximum slope that can be represented by the step size. To avoid slope overload, the step size should be large enough to represent the maximum slope of the input signal.
5. Determining the Test Signal:
To determine the test signal required to avoid slope overload, we need to consider the maximum slope of the speech signals limited to 3.4 kHz.
The maximum slope of a sinusoidal signal can be calculated as the product of the maximum amplitude and the frequency. In this case, the maximum frequency is 3.4 kHz.
Let's assume the maximum amplitude of the speech signal is A. Therefore, the maximum slope can be calculated as:
Maximum slope = A * 3.4 kHz
To avoid slope overload, the step size should be larger than the maximum slope. The step size is given as 100 mV, which is equivalent to 0.1 V.
Therefore, we can set up the following inequality to determine the required test signal:
0.1 V > A * 3.4 kHz
Solving for A:
A < 0.1="" v="" (3.4="" />
Calculating the value:
A < 29.41="" />
Therefore, the test signal required to avoid slope overload is less than 29.41 mV.
Conclusion:
The correct answer is option 'B' (1.08 V) as it is the only option that is less than 29.41 mV, which is the maximum amplitude of the speech signal required to avoid slope overload in the linear delta modulator.
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A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload isa)2.04 Vb)1.08 Vc)4.08 Vd)2.16 VCorrect answer is option 'B'. Can you explain this answer?
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A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload isa)2.04 Vb)1.08 Vc)4.08 Vd)2.16 VCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload isa)2.04 Vb)1.08 Vc)4.08 Vd)2.16 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A linear delta modulator is designed to operate on speech signals limited to 3.4 kHz. The sampling rate is 10 time the Nyquist rate of the speech signal. The step size is 100 m V. The modulator is tested with a this test signal required to avoid slope overload isa)2.04 Vb)1.08 Vc)4.08 Vd)2.16 VCorrect answer is option 'B'. Can you explain this answer?.
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