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I. a2 + 11a + 30 = 0,
II. b2 + 6b + 5 = 0 to solve both the equations to find the values of a and b?
II. b2 + 6b + 5 = 0 to solve both the equations to find the values of a and b?
- a)If a < b
- b)If a ≤ b
- c)If the relationship between a and b cannot be established
- d)If a > b
- e)If a ≥ b
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
I. a2+ 11a + 30 = 0,II. b2+ 6b + 5 = 0 to solve both the equations to ...
Explanation:
I. (a + 6)(a + 5) = 0
=> a = -6, -5
II. (b + 5)(b + 1) = 0
=> b = -5, -1 => a ≤ b
=> a = -6, -5
II. (b + 5)(b + 1) = 0
=> b = -5, -1 => a ≤ b
Most Upvoted Answer
I. a2+ 11a + 30 = 0,II. b2+ 6b + 5 = 0 to solve both the equations to ...
The factor for a²+11a+30 are (a+5)and (a+6) so a=-5 or -6
the factor for b²+6b+5 are (b+5) and (b+1) so b=-5 or -1
Therefore, the only true statement is a≤b
the factor for b²+6b+5 are (b+5) and (b+1) so b=-5 or -1
Therefore, the only true statement is a≤b
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I. a2+ 11a + 30 = 0,II. b2+ 6b + 5 = 0 to solve both the equations to ...
To solve the equations I. a^2 + 11a + 30 = 0 and II. b^2 + 6b + 5 = 0, we can factorize both equations.
I. (a + 5)(a + 6) = 0
Setting each factor equal to zero, we have:
a + 5 = 0 or a + 6 = 0
a = -5 or a = -6
II. (b + 5)(b + 1) = 0
Setting each factor equal to zero, we have:
b + 5 = 0 or b + 1 = 0
b = -5 or b = -1
So, the values of a are -5 and -6, and the values of b are -5 and -1.
I. (a + 5)(a + 6) = 0
Setting each factor equal to zero, we have:
a + 5 = 0 or a + 6 = 0
a = -5 or a = -6
II. (b + 5)(b + 1) = 0
Setting each factor equal to zero, we have:
b + 5 = 0 or b + 1 = 0
b = -5 or b = -1
So, the values of a are -5 and -6, and the values of b are -5 and -1.
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I. a2+ 11a + 30 = 0,II. b2+ 6b + 5 = 0 to solve both the equations to find the values of a and b?a)If a < bb)If a ≤ bc)If the relationship between a and b cannot be establishedd)If a > be)If a ≥ bCorrect answer is option 'B'. Can you explain this answer?
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