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The respective ratio between the two digit of a number is 5:3, if the digit at the one’s place is twice the digit at ten’s place.What is the number ?
  • a)
    63
  • b)
    21
  • c)
    12
  • d)
    Can’t be determined
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?
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The respective ratio between the two digit of a number is 5:3, if the ...
2x/x = 5/3
6x = 5x
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The respective ratio between the two digit of a number is 5:3, if the ...
's place is doubled and the digit at the ten's place is increased by 1, then the new number obtained is 99 more than the original number. Find the original number.

Let the original number be 10x + y, where x and y are the respective digits.

According to the given ratio, we have:

y = (3/5)x

Multiplying both sides by 5, we get:

5y = 3x

Also, the new number obtained by doubling the digit at the one's place and increasing the digit at the ten's place by 1 is:

10x + 2(y+1) = 10x + 2y + 2

Simplifying, we get:

10x + 2y + 2 = 10x + y + 99

Substituting 5y for 3x (from equation 1), we get:

10x + 2(5y/3 + 1) = 10x + 5y/3 + 101

Multiplying both sides by 3, we get:

30x + 10y + 6 = 30x + 5y + 303

Simplifying, we get:

5y = 297

Therefore, y = 59.

Substituting this value in equation 1, we get:

x = 99/5 = 19.8

Since x and y are digits, x must be 19 and not 19.8.

Therefore, the original number is 10x + y = 195.
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The respective ratio between the two digit of a number is 5:3, if the digit at the one’s place is twice the digit at ten’s place.What is the number ?a)63b)21c)12d)Can’t be determinede)None of theseCorrect answer is option 'D'. Can you explain this answer?
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