Quant Exam > Quant Questions > A bag contains 8 blue and 7 green balls. 2 ba...
Start Learning for Free
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?
- a)9/21
- b)8/17
- c)5/14
- d)8/15
- e)9/19
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one ...
When 1st is blue, prob. = 8/15 * 7/14
When 1st is green, prob. = 7/15 * 8/14
Add both cases.
When 1st is green, prob. = 7/15 * 8/14
Add both cases.
Most Upvoted Answer
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one ...
To solve this problem, we can use the concept of conditional probability.
Let's break down the problem step by step:
Step 1: Calculate the probability of drawing a blue ball first.
There are 8 blue balls out of a total of 15 balls in the bag. Therefore, the probability of drawing a blue ball first is 8/15.
Step 2: Calculate the probability of drawing a green ball second, given that a blue ball was drawn first.
After drawing a blue ball, there are now 7 blue balls and 7 green balls left in the bag. Therefore, the probability of drawing a green ball second is 7/14.
Step 3: Calculate the probability of drawing a green ball first.
There are 7 green balls out of a total of 15 balls in the bag. Therefore, the probability of drawing a green ball first is 7/15.
Step 4: Calculate the probability of drawing a blue ball second, given that a green ball was drawn first.
After drawing a green ball, there are now 8 blue balls and 6 green balls left in the bag. Therefore, the probability of drawing a blue ball second is 8/14.
Step 5: Calculate the overall probability of drawing alternately different colored balls.
Since there are two possible scenarios (blue-green or green-blue), we need to calculate the probability for each scenario and then add them together.
Scenario 1: Probability of drawing a blue ball first and then a green ball second = (8/15) * (7/14) = 56/210
Scenario 2: Probability of drawing a green ball first and then a blue ball second = (7/15) * (8/14) = 56/210
Finally, we add the probabilities of both scenarios:
56/210 + 56/210 = 112/210 = 8/15
Therefore, the probability that the balls are alternately of different colors is 8/15, which corresponds to option D.
Let's break down the problem step by step:
Step 1: Calculate the probability of drawing a blue ball first.
There are 8 blue balls out of a total of 15 balls in the bag. Therefore, the probability of drawing a blue ball first is 8/15.
Step 2: Calculate the probability of drawing a green ball second, given that a blue ball was drawn first.
After drawing a blue ball, there are now 7 blue balls and 7 green balls left in the bag. Therefore, the probability of drawing a green ball second is 7/14.
Step 3: Calculate the probability of drawing a green ball first.
There are 7 green balls out of a total of 15 balls in the bag. Therefore, the probability of drawing a green ball first is 7/15.
Step 4: Calculate the probability of drawing a blue ball second, given that a green ball was drawn first.
After drawing a green ball, there are now 8 blue balls and 6 green balls left in the bag. Therefore, the probability of drawing a blue ball second is 8/14.
Step 5: Calculate the overall probability of drawing alternately different colored balls.
Since there are two possible scenarios (blue-green or green-blue), we need to calculate the probability for each scenario and then add them together.
Scenario 1: Probability of drawing a blue ball first and then a green ball second = (8/15) * (7/14) = 56/210
Scenario 2: Probability of drawing a green ball first and then a blue ball second = (7/15) * (8/14) = 56/210
Finally, we add the probabilities of both scenarios:
56/210 + 56/210 = 112/210 = 8/15
Therefore, the probability that the balls are alternately of different colors is 8/15, which corresponds to option D.
|
Explore Courses for Quant exam
|
|
Similar Quant Doubts
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer?
Question Description
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer?.
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer?.
Solutions for A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free.
Here you can find the meaning of A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bag contains 8 blue and 7 green balls. 2 balls are drawn one by one without replacement. What is the probability that the balls are alternately of different colors?a)9/21b)8/17c)5/14d)8/15e)9/19Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Quant tests.
|
|
Explore Courses for Quant exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup