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90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what?
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90 ml of pure dry O2 is subjected to silent electric discharge . If on...
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90 ml of pure dry O2 is subjected to silent electric discharge . If on...
Volume of O3 produced:
Given that 10% of the O2 is converted to O3, we can calculate the volume of O3 produced using the following equation:
Volume of O3 = (10/100) * 90 ml = 9 ml
Volume of the mixture of gases (O2 and O3) after the reaction:
After the reaction, the volume of the mixture will be the sum of the remaining O2 and the O3 produced. The remaining O2 is 90 ml - 9 ml = 81 ml.
Therefore, the volume of the mixture of gases after the reaction is 81 ml + 9 ml = 90 ml.
Passing through turpentine oil:
When the mixture of gases (O2 and O3) passes through turpentine oil, the O3 reacts with the turpentine oil to form a solid compound, while the O2 remains unaffected.
The reaction between O3 and turpentine oil can be represented as follows:
O3 + C10H16 (turpentine oil) → CO2 + H2O + solid compound
The solid compound formed is insoluble in the turpentine oil and separates out as a precipitate. This reaction is used to remove O3 from the mixture.
The volume of the mixture after passing through turpentine oil will only contain O2, as the O3 has reacted and been removed. Therefore, the volume of the mixture after passing through turpentine oil will be 81 ml, which is the remaining volume of O2.
Given that 10% of the O2 is converted to O3, we can calculate the volume of O3 produced using the following equation:
Volume of O3 = (10/100) * 90 ml = 9 ml
Volume of the mixture of gases (O2 and O3) after the reaction:
After the reaction, the volume of the mixture will be the sum of the remaining O2 and the O3 produced. The remaining O2 is 90 ml - 9 ml = 81 ml.
Therefore, the volume of the mixture of gases after the reaction is 81 ml + 9 ml = 90 ml.
Passing through turpentine oil:
When the mixture of gases (O2 and O3) passes through turpentine oil, the O3 reacts with the turpentine oil to form a solid compound, while the O2 remains unaffected.
The reaction between O3 and turpentine oil can be represented as follows:
O3 + C10H16 (turpentine oil) → CO2 + H2O + solid compound
The solid compound formed is insoluble in the turpentine oil and separates out as a precipitate. This reaction is used to remove O3 from the mixture.
The volume of the mixture after passing through turpentine oil will only contain O2, as the O3 has reacted and been removed. Therefore, the volume of the mixture after passing through turpentine oil will be 81 ml, which is the remaining volume of O2.
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90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what?
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90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what?.
90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 90 ml of pure dry O2 is subjected to silent electric discharge . If only 10% of it is converted to O3 , volume of the mixture of gases (O2 and O3) after the reaction will be what and after passing through turpentine oil will be what?.
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