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A speak truth in 60% cases and B in 80% cases. In what percent of cases they likely to contradict each other narrating the same incident?
- a)9/25
- b)7/25
- c)11/25
- d)13/25
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A speak truth in 60% cases and B in 80% cases. In what percent of case...
P(A) = 3/5 and P(B) = 4/5. Now they are contradicting means one is telling truth and other telling the lie.
So, Probability = (3/5)*(1/5) + (2/5)*(4/5)
So, Probability = (3/5)*(1/5) + (2/5)*(4/5)
Most Upvoted Answer
A speak truth in 60% cases and B in 80% cases. In what percent of case...
To find the percentage of cases in which A and B contradict each other, we need to consider the cases where A speaks the truth and B lies, and the cases where A lies and B speaks the truth.
Let's assume we have 100 cases to analyze.
A speaks the truth in 60% of the cases, which means A lies in the remaining 40% of the cases.
Similarly, B speaks the truth in 80% of the cases, which means B lies in the remaining 20% of the cases.
Now let's calculate the cases where A speaks the truth and B lies:
A speaks the truth in 60% of the cases, and B lies in 20% of the cases. Therefore, the percentage of cases where A speaks the truth and B lies is 60% * 20% = 12%.
Next, let's calculate the cases where A lies and B speaks the truth:
A lies in 40% of the cases, and B speaks the truth in 80% of the cases. Therefore, the percentage of cases where A lies and B speaks the truth is 40% * 80% = 32%.
To find the total percentage of cases where A and B contradict each other, we add the two percentages calculated above:
12% + 32% = 44%.
Therefore, in 44% of the cases, A and B are likely to contradict each other while narrating the same incident.
However, none of the given options match the calculated result. So, the correct answer is None of these.
Let's assume we have 100 cases to analyze.
A speaks the truth in 60% of the cases, which means A lies in the remaining 40% of the cases.
Similarly, B speaks the truth in 80% of the cases, which means B lies in the remaining 20% of the cases.
Now let's calculate the cases where A speaks the truth and B lies:
A speaks the truth in 60% of the cases, and B lies in 20% of the cases. Therefore, the percentage of cases where A speaks the truth and B lies is 60% * 20% = 12%.
Next, let's calculate the cases where A lies and B speaks the truth:
A lies in 40% of the cases, and B speaks the truth in 80% of the cases. Therefore, the percentage of cases where A lies and B speaks the truth is 40% * 80% = 32%.
To find the total percentage of cases where A and B contradict each other, we add the two percentages calculated above:
12% + 32% = 44%.
Therefore, in 44% of the cases, A and B are likely to contradict each other while narrating the same incident.
However, none of the given options match the calculated result. So, the correct answer is None of these.
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