The average marks obtained by 100 candidates in an examination are 45....
Answer – c) 50 Explanation : Let P = passed students and failed students = F. So 45*100 = 50*P + 40*F and P + F = 100. Solve for F and P, we will get P = 50.
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The average marks obtained by 100 candidates in an examination are 45....
Let's assume the number of students who passed the examination is 'x'. Since the average marks obtained by 100 candidates is 45, we can find the total marks obtained by all the candidates.
Total marks obtained by all candidates = Average marks * Number of candidates
= 45 * 100
= 4500
Similarly, we can find the total marks obtained by the passed students and the failed students.
Total marks obtained by passed students = Average marks of passed students * Number of passed students
= 50 * x
= 50x
Total marks obtained by failed students = Average marks of failed students * Number of failed students
= 40 * (100 - x)
= 40(100 - x)
Now, since the total marks obtained by all the candidates is equal to the total marks obtained by the passed students plus the total marks obtained by the failed students, we can write the equation:
4500 = 50x + 40(100 - x)
Simplifying the equation, we get:
4500 = 50x + 4000 - 40x
500 = 10x
x = 50
Therefore, the number of students who passed the examination is 50.
Hence, the correct answer is option 'C'.
The average marks obtained by 100 candidates in an examination are 45....
Average is 45
candidate is 100
100×45=4500
average passing Mark's is 50(50×50=2500)
average fail marks 40(40×50=2000)
:-2500+2000=4500
2500÷50=50