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Suresh started his journey from P to Q by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from Q to R. Then he returned from R to P via Q at the speed of 24 kmph. The average speed of the whole trip is:
- a)18.5 kmph
- b)19.8 kmph
- c)18.2 kmph
- d)19.2 kmph
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
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Suresh started his journey from P to Q by his bike at the speed of 40 ...
Answer – D. 19.2 kmph Explanation: Average speed from P to R = 2 * 40 * 10 / (40 + 10) = 16 kmph Average Speed = 2 * 16 * 24 / (16 + 24) = 19.2 kmph
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Suresh started his journey from P to Q by his bike at the speed of 40 ...
To find the average speed of the whole trip, we need to calculate the total distance traveled and the total time taken.
1. Distance from P to Q:
Suresh traveled from P to Q on his bike at a speed of 40 kmph. Let's assume the distance between P and Q is 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 40
2. Distance from Q to R:
After reaching Q, Suresh traveled from Q to R on foot at a speed of 10 kmph. The distance between Q and R is also 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 10
3. Distance from R to P:
After reaching R, Suresh returned to P via Q at a speed of 24 kmph. The distance between R and P is again 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 24
4. Total distance traveled:
Since Suresh traveled the same distance from P to Q, Q to R, and R to P, the total distance traveled is 3d km.
5. Total time taken:
To calculate the total time taken, we add the individual times taken for each leg of the journey:
Total Time = d/40 + d/10 + d/24
6. Average speed:
Average Speed = Total Distance / Total Time
Substituting the values:
Average Speed = 3d / (d/40 + d/10 + d/24)
Simplifying the expression:
Average Speed = 3 / (1/40 + 1/10 + 1/24)
To add the fractions, we need to find the least common denominator (LCD), which is 120 in this case. Converting the fractions:
Average Speed = 3 / (3/120 + 12/120 + 5/120)
Average Speed = 3 / (20/120)
Average Speed = 3 * 120 / 20
Average Speed = 18 kmph
Therefore, the average speed of the whole trip is 18 kmph, which corresponds to option (d).
1. Distance from P to Q:
Suresh traveled from P to Q on his bike at a speed of 40 kmph. Let's assume the distance between P and Q is 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 40
2. Distance from Q to R:
After reaching Q, Suresh traveled from Q to R on foot at a speed of 10 kmph. The distance between Q and R is also 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 10
3. Distance from R to P:
After reaching R, Suresh returned to P via Q at a speed of 24 kmph. The distance between R and P is again 'd' km. Therefore, the time taken to cover this distance is given by:
Time = Distance / Speed
Time = d / 24
4. Total distance traveled:
Since Suresh traveled the same distance from P to Q, Q to R, and R to P, the total distance traveled is 3d km.
5. Total time taken:
To calculate the total time taken, we add the individual times taken for each leg of the journey:
Total Time = d/40 + d/10 + d/24
6. Average speed:
Average Speed = Total Distance / Total Time
Substituting the values:
Average Speed = 3d / (d/40 + d/10 + d/24)
Simplifying the expression:
Average Speed = 3 / (1/40 + 1/10 + 1/24)
To add the fractions, we need to find the least common denominator (LCD), which is 120 in this case. Converting the fractions:
Average Speed = 3 / (3/120 + 12/120 + 5/120)
Average Speed = 3 / (20/120)
Average Speed = 3 * 120 / 20
Average Speed = 18 kmph
Therefore, the average speed of the whole trip is 18 kmph, which corresponds to option (d).
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Suresh started his journey from P to Q by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from Q to R. Then he returned from R to P via Q at the speed of 24 kmph. The average speed of the whole trip is:a)18.5 kmphb)19.8 kmphc)18.2 kmphd)19.2 kmphe)None of theseCorrect answer is option 'D'. Can you explain this answer?
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Suresh started his journey from P to Q by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from Q to R. Then he returned from R to P via Q at the speed of 24 kmph. The average speed of the whole trip is:a)18.5 kmphb)19.8 kmphc)18.2 kmphd)19.2 kmphe)None of theseCorrect answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Suresh started his journey from P to Q by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from Q to R. Then he returned from R to P via Q at the speed of 24 kmph. The average speed of the whole trip is:a)18.5 kmphb)19.8 kmphc)18.2 kmphd)19.2 kmphe)None of theseCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suresh started his journey from P to Q by his bike at the speed of 40 kmph and then, the same distance he travelled on his foot at the speed of 10 kmph from Q to R. Then he returned from R to P via Q at the speed of 24 kmph. The average speed of the whole trip is:a)18.5 kmphb)19.8 kmphc)18.2 kmphd)19.2 kmphe)None of theseCorrect answer is option 'D'. Can you explain this answer?.
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