Propanone is a ketone and ketones don't react with fehlings solution.so B is the correct choice.

Propanone does not react with Fehling solution
Propanone, also known as acetone, does not react with Fehling solution due to the absence of aldehyde or reducing functional groups in its structure. Let's break down the explanation further:

Fehling Solution:
Fehling solution is a chemical reagent used to differentiate between aldehydes and ketones based on their ability to reduce copper(II) ions to copper(I) ions. It consists of two separate solutions: Fehling solution A (copper(II) sulfate) and Fehling solution B (sodium potassium tartrate in sodium hydroxide).

Acetaldehyde:
Acetaldehyde is an aldehyde that can react with Fehling solution due to the presence of the aldehyde functional group (-CHO). It can reduce the copper(II) ions in Fehling solution to form a red precipitate of copper(I) oxide.

Glucose:
Glucose is a reducing sugar that can also react with Fehling solution because it contains an aldehyde group in its structure. The aldehyde group in glucose allows it to reduce copper(II) ions and form a red precipitate.

Formic Acid:
Formic acid, although not a sugar or an aldehyde, can also react with Fehling solution because it is a reducing agent. It can reduce copper(II) ions and produce a red precipitate in the presence of Fehling solution.

Propanone:
Propanone, on the other hand, is a ketone that does not have an aldehyde functional group. Ketones do not react with Fehling solution because they lack the necessary functional group to reduce copper(II) ions. Therefore, propanone does not produce a red precipitate when mixed with Fehling solution.
In conclusion, propanone does not react with Fehling solution because it is a ketone without an aldehyde group.