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A Boat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?
- a)6 Km/hr
- b)9 Km/hr
- c)12 Km/hr
- d)15 Km/hr
- e)None
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
ABoat takes 128 min less to travel to 48 Km downstream than to travel ...
Answer – 3. 12 Km/hr Explanation : 32/15 = 48(1/s-3 – 1/s+3) s= 12
Most Upvoted Answer
ABoat takes 128 min less to travel to 48 Km downstream than to travel ...
Given data:
Distance = 48 Km
Speed of stream = 3 Km/hr
Let the speed of the boat in still water be x km/hr
When the boat travels downstream:
Speed of the boat = (x + 3) km/hr
Time taken = distance/speed = 48/(x + 3) hr
When the boat travels upstream:
Speed of the boat = (x - 3) km/hr
Time taken = distance/speed = 48/(x - 3) hr
According to the question,
Time taken downstream - Time taken upstream = 128 min
i.e., 48/(x + 3) - 48/(x - 3) = 128/60
Simplifying this equation, we get:
12x = 169
x = 169/12 = 14.083 km/hr
Therefore, the speed of the boat in still water is 14.083 km/hr, which is closest to option C (12 km/hr).
Distance = 48 Km
Speed of stream = 3 Km/hr
Let the speed of the boat in still water be x km/hr
When the boat travels downstream:
Speed of the boat = (x + 3) km/hr
Time taken = distance/speed = 48/(x + 3) hr
When the boat travels upstream:
Speed of the boat = (x - 3) km/hr
Time taken = distance/speed = 48/(x - 3) hr
According to the question,
Time taken downstream - Time taken upstream = 128 min
i.e., 48/(x + 3) - 48/(x - 3) = 128/60
Simplifying this equation, we get:
12x = 169
x = 169/12 = 14.083 km/hr
Therefore, the speed of the boat in still water is 14.083 km/hr, which is closest to option C (12 km/hr).
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Community Answer
ABoat takes 128 min less to travel to 48 Km downstream than to travel ...
Speed of stream = 3km/hr
Distance = 48km
consider T1=time during downstream
T2=time during upstream
Condition given: T2-T1=128minutes = 128/60 hours
To find : SPEED OF BOAT IN STILL WATER (let's assume u)
Solution :- T2= 48/(u-3)
T1=48/(u+3)
using: T2-T1= 128/60
48/(u-3) - 48/(u+3)= 128/60
After taking LCM we get
288/(u²-9) =128/60
u²-9=(288×60)/128
u²-9= 15×9
u²= 135+9
u²= 144
u=12km/hr
so option C is the correct answer
Distance = 48km
consider T1=time during downstream
T2=time during upstream
Condition given: T2-T1=128minutes = 128/60 hours
To find : SPEED OF BOAT IN STILL WATER (let's assume u)
Solution :- T2= 48/(u-3)
T1=48/(u+3)
using: T2-T1= 128/60
48/(u-3) - 48/(u+3)= 128/60
After taking LCM we get
288/(u²-9) =128/60
u²-9=(288×60)/128
u²-9= 15×9
u²= 135+9
u²= 144
u=12km/hr
so option C is the correct answer
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ABoat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?a)6 Km/hrb)9 Km/hrc)12 Km/hrd)15 Km/hre)NoneCorrect answer is option 'C'. Can you explain this answer?
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ABoat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?a)6 Km/hrb)9 Km/hrc)12 Km/hrd)15 Km/hre)NoneCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about ABoat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?a)6 Km/hrb)9 Km/hrc)12 Km/hrd)15 Km/hre)NoneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ABoat takes 128 min less to travel to 48 Km downstream than to travel the same distance upstream. If the speed of the stream is 3 Km/hr. Then Speed of Boat in still water is?a)6 Km/hrb)9 Km/hrc)12 Km/hrd)15 Km/hre)NoneCorrect answer is option 'C'. Can you explain this answer?.
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