In what ratio must the 3 varieties of wheat costing Rs 42, Rs 54 and R...
E) 7 : 7 : 20
Explanation: SP = 63.8, Profit=10%, so CP = (100/110)*63.8 = 58 Now 58 is greater than 42 and 54 and less than 65 So 42 65
. 58
7 16
And 54 65
. 58
7 4
So 1 part of 1st wheat A, 1 part of 2nd wheat B and 2 parts of 3rd wheat C gives A : C = 7 : 16, and B : C = 7 : 4 So A : B : C = 7 : 7 : (16+4) *we have taken 2 parts of C so it is added – when there are 3 varieties to be mixed it is not done like simple calculation of A : C and B : C
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In what ratio must the 3 varieties of wheat costing Rs 42, Rs 54 and R...
To find the ratio in which the three varieties of wheat should be mixed, we need to consider the costs and the desired selling price.
Let's assume the quantities of the three varieties of wheat as x, y, and z respectively.
Cost Calculation:
The cost of variety 1 (Rs 42) per unit is 42x.
The cost of variety 2 (Rs 54) per unit is 54y.
The cost of variety 3 (Rs 65) per unit is 65z.
The total cost of the mixture is the sum of the costs of the three varieties:
Total Cost = 42x + 54y + 65z
Selling Price Calculation:
We want to sell the mixture at a selling price of Rs 63.8 per unit, which includes a profit of 10%.
So, the cost price per unit is (100/110) * Rs 63.8 = Rs 58.
Now, we can equate the selling price to the cost price to find the ratio:
42x + 54y + 65z = 58(x + y + z)
Simplifying the equation:
42x + 54y + 65z = 58x + 58y + 58z
42x - 58x + 54y - 58y + 65z - 58z = 0
-16x - 4y + 7z = 0
Ratio Calculation:
To find a suitable ratio, we need to find integer values for x, y, and z that satisfy the equation -16x - 4y + 7z = 0.
Let's try different values of z and find corresponding values of x and y.
When z = 7, the equation becomes:
-16x - 4y + 7(7) = 0
-16x - 4y + 49 = 0
-16x - 4y = -49
By trying different values, we find that x = -3 and y = 1 satisfy the equation. However, we need positive values for the quantities.
So, let's try z = 14. The equation becomes:
-16x - 4y + 7(14) = 0
-16x - 4y + 98 = 0
-16x - 4y = -98
By trying different values, we find that x = -5 and y = -2 satisfy the equation. Again, we need positive values for the quantities.
Finally, let's try z = 21. The equation becomes:
-16x - 4y + 7(21) = 0
-16x - 4y + 147 = 0
-16x - 4y = -147
By trying different values, we find that x = -7 and y = -4 satisfy the equation. Again, we need positive values for the quantities.
Hence, the suitable ratio is x : y : z = 7 : 7 : 20, which is option E.