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How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.
- a)10 kg
- b)40 kg
- c)24 kg
- d)25 kg
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
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How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 ...
Answer – a) 10 kg Explanation : by rule of alligation, 20 32
…….28………..
4 8
So, x = 10
…….28………..
4 8
So, x = 10
Most Upvoted Answer
How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 ...
Problem Statement:
Find the amount of rice A that needs to be mixed with rice B to obtain a profit of 25% on selling them at 35 rupees per kg.
Given:
Cost of rice A = Rs. 20 per kg
Cost of rice B = Rs. 32 per kg
Selling price = Rs. 35 per kg
Profit percentage = 25%
Quantity of rice B = 20 kg
Solution:
Let the amount of rice A needed be x kg.
Total quantity of mixture = x + 20 kg
Let the cost price of the mixture be C.
Cost of rice A = 20x
Cost of rice B = 32 x 20 = 640
Total cost = 20x + 640
We need to find the selling price of the mixture to obtain a profit of 25%. Let the selling price be S.
Profit percentage = (S - C) / C * 100
25 = (S - C) / C * 100
S - C = 0.25C
S = 1.25C
S = 1.25(20x + 640)
S = 25x + 800
We know that selling price per kg = Rs. 35
So, (25x + 800) / (x + 20) = 35
25x + 800 = 35x + 700
10x = 100
x = 10
Therefore, 10 kg of rice A costing Rs. 20 per kg needs to be mixed with 20 kg of rice B costing Rs. 32 per kg to obtain a profit of 25% by selling the mixture at Rs. 35 per kg.
Find the amount of rice A that needs to be mixed with rice B to obtain a profit of 25% on selling them at 35 rupees per kg.
Given:
Cost of rice A = Rs. 20 per kg
Cost of rice B = Rs. 32 per kg
Selling price = Rs. 35 per kg
Profit percentage = 25%
Quantity of rice B = 20 kg
Solution:
Let the amount of rice A needed be x kg.
Total quantity of mixture = x + 20 kg
Let the cost price of the mixture be C.
Cost of rice A = 20x
Cost of rice B = 32 x 20 = 640
Total cost = 20x + 640
We need to find the selling price of the mixture to obtain a profit of 25%. Let the selling price be S.
Profit percentage = (S - C) / C * 100
25 = (S - C) / C * 100
S - C = 0.25C
S = 1.25C
S = 1.25(20x + 640)
S = 25x + 800
We know that selling price per kg = Rs. 35
So, (25x + 800) / (x + 20) = 35
25x + 800 = 35x + 700
10x = 100
x = 10
Therefore, 10 kg of rice A costing Rs. 20 per kg needs to be mixed with 20 kg of rice B costing Rs. 32 per kg to obtain a profit of 25% by selling the mixture at Rs. 35 per kg.
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How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.a)10 kgb)40 kgc)24 kgd)25 kge)None of theseCorrect answer is option 'A'. Can you explain this answer?
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How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.a)10 kgb)40 kgc)24 kgd)25 kge)None of theseCorrect answer is option 'A'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.a)10 kgb)40 kgc)24 kgd)25 kge)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many Kgs of rice A costing rupees 20 per kg must be mixed with 20 kg of rice B costing rupees 32 per kg, so that after selling them at 35 rupees per kg, he gets a profit of 25%.a)10 kgb)40 kgc)24 kgd)25 kge)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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