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 In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respectively. 20 kg of first alloy and 32 kg of second alloy and some pure zinc are melted together.An alloy is obtained in which the ratio of copper and zinc was 3:5. Find the quantity of zinc melted.
  • a)
    65/3 kg
  • b)
    67/3 kg
  • c)
    68/3 kg
  • d)
    71/3 kg
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respecti...
Answer – c) 68/3 kg Explanation : Copper = 1/5*20 + 3/4*32 = 28kg zinc = 4/5*20 + 1/4*32 = 24kg now x kg of zinc is added, so [28/24 + x] = 3/5. X = 68/3 kg
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In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respecti...
Given:
- Ratio of copper and zinc in alloy 1 = 1:4
- Ratio of copper and zinc in alloy 2 = 3:1
- Quantity of alloy 1 = 20 kg
- Quantity of alloy 2 = 32 kg
- Ratio of copper and zinc in final alloy = 3:5

To find:
- Quantity of pure zinc melted

Solution:
1. Let's first calculate the amount of copper and zinc in the two alloys:

- Alloy 1: Copper = (1/5)*20 kg = 4 kg, Zinc = (4/5)*20 kg = 16 kg
- Alloy 2: Copper = (3/4)*32 kg = 24 kg, Zinc = (1/4)*32 kg = 8 kg

2. Let's assume that x kg of pure zinc was melted.

3. Now, let's calculate the amount of copper and zinc in the final alloy:

- Let the quantity of final alloy be y kg
- Copper in final alloy = (3/8)*y + 4 + 24 = (3/8)*y + 28
- Zinc in final alloy = (5/8)*y + 16 + 8 + x = (5/8)*y + 24 + x

4. We know that the ratio of copper and zinc in the final alloy is 3:5. Therefore:

- (Copper in final alloy) / (Zinc in final alloy) = 3/5
- ((3/8)*y + 28) / ((5/8)*y + 24 + x) = 3/5

5. Solving for y, we get:

- y = (40/3) + (8/3)*x

6. We also know that the total quantity of alloy and pure zinc melted is 20 + 32 + x = (52 + x) kg. Therefore:

- y + x = 52 + x
- y = 52

7. Substituting the value of y in equation (5), we get:

- (3/8)*y + 28 = (5/8)*y + 24 + x
- (3/8)*52 + 28 = (5/8)*52 + 24 + x
- 27 = 13 + x
- x = 14

Therefore, the quantity of pure zinc melted is 14 kg.

Answer: Option (c) 68/3 kg.
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In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respectively. 20 kg of first alloy and 32 kg of second alloy and some pure zinc are melted together.An alloy is obtained in which the ratio of copper and zinc was 3:5. Find the quantity of zinc melted.a)65/3 kgb)67/3 kgc)68/3 kgd)71/3 kge)None of theseCorrect answer is option 'C'. Can you explain this answer?
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In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respectively. 20 kg of first alloy and 32 kg of second alloy and some pure zinc are melted together.An alloy is obtained in which the ratio of copper and zinc was 3:5. Find the quantity of zinc melted.a)65/3 kgb)67/3 kgc)68/3 kgd)71/3 kge)None of theseCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respectively. 20 kg of first alloy and 32 kg of second alloy and some pure zinc are melted together.An alloy is obtained in which the ratio of copper and zinc was 3:5. Find the quantity of zinc melted.a)65/3 kgb)67/3 kgc)68/3 kgd)71/3 kge)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In two alloys copper and zinc are in the ratio of 1:4 and 3:1 respectively. 20 kg of first alloy and 32 kg of second alloy and some pure zinc are melted together.An alloy is obtained in which the ratio of copper and zinc was 3:5. Find the quantity of zinc melted.a)65/3 kgb)67/3 kgc)68/3 kgd)71/3 kge)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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