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Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared
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the Physics exam syllabus. Information about Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam.
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Here you can find the meaning of Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer?, a detailed solution for Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? has been provided alongside types of Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Cosmic ray muons generated at the top of the Earths atmosphere decay according to the radioactive decay lawWhere N(t) is the number of muons at time t and T1/2 = 1.52 μsec is the proper half - life of the muon. Immediately after generation, most of these muons shoot down towards the earths surface. Some of these muons decay on the way but their interaction with atmosphere is negligible. An observer on the top of a mountain of height 2 km above mean sea level detects muons with the speed 0.98 cover a period of time and counts 1000 muons. The number of muons of the same speed detected by an observer at mean sea level in the same period of time would be____.Correct answer is '539'. Can you explain this answer? tests, examples and also practice Physics tests.