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A full wave rectifier supplies a load of 1 kΩ. The a.c. Voltage applied to the diodes is 220 - 0 - 220 Volts rms. If diode resistance is neglected, then Average d.c. Voltage
- a)220 V
- b)200 V
- c)198 V
- d)0 volts
Correct answer is option 'C'. Can you explain this answer?
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A full wave rectifier supplies a load of 1 kΩ. The a.c. Voltage applie...
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Problem Statement: A full wave rectifier supplies a load of 1 kΩ. The a.c. Voltage applied to the diodes is 220 - 0 - 220 Volts rms. Neglecting diode resistance, find the average d.c. voltage.
Solution:
Full Wave Rectifier: A full wave rectifier is a circuit that converts the entire input waveform into a pulsating DC waveform. In a full wave rectifier, the input AC voltage is applied to the diodes in such a way that both the positive and negative half cycles are rectified. The output waveform of the full wave rectifier is shown below:
Average DC voltage: The average DC voltage of a rectifier is the DC equivalent of the input AC voltage. The average DC voltage can be calculated using the following formula:
Vavg = (2Vm/π)
where Vm is the maximum value of the input AC voltage.
Given:
Load resistance, R = 1 kΩ
AC voltage applied to the diodes, Vrms = 220 - 0 - 220 Volts
Neglect diode resistance
Calculation:
The maximum value of the input AC voltage is given by:
Vm = Vrms * √2
Vm = 220 * √2
Vm = 311.13 V
The average DC voltage can be calculated using the formula:
Vavg = (2Vm/π)
Vavg = (2 * 311.13)/π
Vavg = 198.05 V
Therefore, the average DC voltage is 198 V.
Answer: option (c)
Solution:
Full Wave Rectifier: A full wave rectifier is a circuit that converts the entire input waveform into a pulsating DC waveform. In a full wave rectifier, the input AC voltage is applied to the diodes in such a way that both the positive and negative half cycles are rectified. The output waveform of the full wave rectifier is shown below:
Average DC voltage: The average DC voltage of a rectifier is the DC equivalent of the input AC voltage. The average DC voltage can be calculated using the following formula:
Vavg = (2Vm/π)
where Vm is the maximum value of the input AC voltage.
Given:
Load resistance, R = 1 kΩ
AC voltage applied to the diodes, Vrms = 220 - 0 - 220 Volts
Neglect diode resistance
Calculation:
The maximum value of the input AC voltage is given by:
Vm = Vrms * √2
Vm = 220 * √2
Vm = 311.13 V
The average DC voltage can be calculated using the formula:
Vavg = (2Vm/π)
Vavg = (2 * 311.13)/π
Vavg = 198.05 V
Therefore, the average DC voltage is 198 V.
Answer: option (c)
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A full wave rectifier supplies a load of 1 kΩ. The a.c. Voltage applied to the diodes is 220 - 0 - 220 Volts rms. If diode resistance is neglected, then Average d.c. Voltagea)220 Vb)200 Vc)198 Vd)0 voltsCorrect answer is option 'C'. Can you explain this answer?
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