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The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]
- a)1/8
- b)3/8
- c)5/8
- d)7/8
Correct answer is option 'B'. Can you explain this answer?
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To calculate the de-Broglie wavelength of a particle, we can use the de-Broglie wavelength formula:
λ = h / p
where λ is the de-Broglie wavelength, h is Planck's constant (approximately 6.626 x 10^-34 J·s), and p is the momentum of the particle.
The momentum of a particle can be calculated using the formula:
p = m * v
where p is the momentum, m is the mass of the particle, and v is the velocity of the particle.
In this case, the velocity of the particle is given as 2.25 x 10^8 m/s. Let's assume the mass of the particle is 1 kg for simplicity.
Using the formula for momentum:
p = m * v
p = 1 kg * 2.25 x 10^8 m/s
p = 2.25 x 10^8 kg·m/s
Now, we can substitute the value of momentum into the de-Broglie wavelength formula:
λ = h / p
λ = (6.626 x 10^-34 J·s) / (2.25 x 10^8 kg·m/s)
Calculating the de-Broglie wavelength:
λ ≈ 2.94 x 10^-42 m
Therefore, the de-Broglie wavelength of the particle moving with a velocity of 2.25 x 10^8 m/s is approximately 2.94 x 10^-42 m.
λ = h / p
where λ is the de-Broglie wavelength, h is Planck's constant (approximately 6.626 x 10^-34 J·s), and p is the momentum of the particle.
The momentum of a particle can be calculated using the formula:
p = m * v
where p is the momentum, m is the mass of the particle, and v is the velocity of the particle.
In this case, the velocity of the particle is given as 2.25 x 10^8 m/s. Let's assume the mass of the particle is 1 kg for simplicity.
Using the formula for momentum:
p = m * v
p = 1 kg * 2.25 x 10^8 m/s
p = 2.25 x 10^8 kg·m/s
Now, we can substitute the value of momentum into the de-Broglie wavelength formula:
λ = h / p
λ = (6.626 x 10^-34 J·s) / (2.25 x 10^8 kg·m/s)
Calculating the de-Broglie wavelength:
λ ≈ 2.94 x 10^-42 m
Therefore, the de-Broglie wavelength of the particle moving with a velocity of 2.25 x 10^8 m/s is approximately 2.94 x 10^-42 m.
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The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer?
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The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer?.
The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de-Broglie wavelength of a particle moving with a velocity 2.25 x 108 ms−1 is equal to the wavelength of a photon. The ratio of kinetic energy of the particle to the energy of the photon is [velocity of light = 3 x 108 ms−1 is]a)1/8b)3/8c)5/8d)7/8Correct answer is option 'B'. Can you explain this answer?.
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