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In a full wave rectifier circuit using centre tapped transformer, the peak voltage across half of the secondary winding is 30 V. Then PIV is
- a)30 V
- b)60 V
- c)15 V
- d)10 V
Correct answer is option 'B'. Can you explain this answer?
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In a full wave rectifier circuit using centre tapped transformer, the ...
In full wave circuit using centre tapped transformer PIV = 2Vm .
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In a full wave rectifier circuit using centre tapped transformer, the ...
Explanation:
Full wave Rectifier: A full-wave rectifier is a circuit that allows alternating current (AC) to be converted into a direct current (DC). In this circuit, both the half cycles of the input AC voltage are utilized to produce the output voltage. There are two types of full-wave rectifiers: center-tapped and bridge rectifiers.
Center-tapped Full Wave Rectifier: A center-tapped full-wave rectifier uses a center-tapped transformer and two diodes to rectify both half-cycles of the AC input. The center-tapped transformer provides two identical secondary windings that are 180 degrees out of phase. The two diodes are connected to the ends of the secondary winding, and the center tap is the common connection to the load.
Peak Inverse Voltage (PIV): The maximum voltage that a diode can withstand in the reverse-biased condition is called Peak Inverse Voltage (PIV). In a full-wave rectifier, the PIV across each diode is equal to the peak voltage of the secondary winding.
Given:
Peak voltage across half of the secondary winding = 30 V
Solution:
The peak voltage across the entire secondary winding is given by:
Peak voltage = 2 x Peak voltage across half of the secondary winding
= 2 x 30 V
= 60 V
Therefore, the PIV across each diode in the center-tapped full-wave rectifier is equal to the peak voltage of the secondary winding, which is 60 V. Hence, the correct answer is option (B).
Full wave Rectifier: A full-wave rectifier is a circuit that allows alternating current (AC) to be converted into a direct current (DC). In this circuit, both the half cycles of the input AC voltage are utilized to produce the output voltage. There are two types of full-wave rectifiers: center-tapped and bridge rectifiers.
Center-tapped Full Wave Rectifier: A center-tapped full-wave rectifier uses a center-tapped transformer and two diodes to rectify both half-cycles of the AC input. The center-tapped transformer provides two identical secondary windings that are 180 degrees out of phase. The two diodes are connected to the ends of the secondary winding, and the center tap is the common connection to the load.
Peak Inverse Voltage (PIV): The maximum voltage that a diode can withstand in the reverse-biased condition is called Peak Inverse Voltage (PIV). In a full-wave rectifier, the PIV across each diode is equal to the peak voltage of the secondary winding.
Given:
Peak voltage across half of the secondary winding = 30 V
Solution:
The peak voltage across the entire secondary winding is given by:
Peak voltage = 2 x Peak voltage across half of the secondary winding
= 2 x 30 V
= 60 V
Therefore, the PIV across each diode in the center-tapped full-wave rectifier is equal to the peak voltage of the secondary winding, which is 60 V. Hence, the correct answer is option (B).
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In a full wave rectifier circuit using centre tapped transformer, the peak voltage across half of the secondary winding is 30 V. Then PIV isa)30 Vb)60 Vc)15 Vd)10 VCorrect answer is option 'B'. Can you explain this answer?
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