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A sum of rupees 4800 is lent out in two parts in such a way that the interest on one part at 10% for 4 years is equal to that on another part at 8% for 7 years.Find the two sums
  • a)
    2800, 2000
  • b)
    2400, 2400
  • c)
    2600, 2200
  • d)
    2700, 2100
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A sum of rupees 4800 is lent out in two parts in such a way that the i...
Answer – a) 2800, 2000 Explanation : Let first part is A then second will be 4800 – A A*(10/100)*4 = (4800 – A)*(8/100)*7
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A sum of rupees 4800 is lent out in two parts in such a way that the i...
Given:
- Total sum lent = Rs. 4800
- Interest on one part at 10% for 4 years = Interest on another part at 8% for 7 years

To find: The two sums

Let's assume that one part is x and the other part is (4800-x)

We know that Interest = (Principal*Rate*Time)/100

Using this formula, we can write the given condition as:

(x*10*4)/100 = ((4800-x)*8*7)/100

Simplifying this equation, we get:

40x = 26880 - 56x

96x = 26880

x = 2800

So, one part is Rs. 2800 and the other part is (4800-2800) = Rs. 2000.

Therefore, the answer is option A, i.e., 2800 and 2000.
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A sum of rupees 4800 is lent out in two parts in such a way that the interest on one part at 10% for 4 years is equal to that on another part at 8% for 7 years.Find the two sumsa)2800, 2000b)2400, 2400c)2600, 2200d)2700, 2100e)None of theseCorrect answer is option 'A'. Can you explain this answer?
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