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A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is?
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Finding the frequency of a simple pendulum in a moving car
Formula for the frequency of a simple pendulum
The frequency of a simple pendulum is given by the formula:
f = 1/2π √(g/L)
Where f is the frequency, g is the acceleration due to gravity, and L is the length of the pendulum.
Effect of circular motion on the pendulum
When the car moves in a circular path, the pendulum experiences a centrifugal force that acts away from the center of the circle. This force affects the equilibrium position of the pendulum, causing it to shift to one side.
Equilibrium position of the pendulum
The new equilibrium position of the pendulum can be found by balancing the gravitational force and the centrifugal force. The gravitational force is given by:
Fg = mg
Where m is the mass of the pendulum and g is the acceleration due to gravity. The centrifugal force is given by:
Fc = mv^2/R
Where v is the velocity of the car and R is the radius of the circle.
Frequency of the pendulum in the moving car
The frequency of the pendulum in the moving car can be found by using the new equilibrium position of the pendulum. The length of the pendulum is now the distance from the new equilibrium position to the center of the circle, which is given by:
L' = L + Fc/mg
Substituting this into the formula for the frequency of the pendulum, we get:
f' = 1/2π √(g/L')
Simplifying this equation, we get:
f' = 1/2π √(g/(L + Fc/mg))
This is the frequency of the pendulum in the moving car.
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A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is?
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A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is?.
A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simple pendulum of length m and mass m is suspended in a car that is travelling was a constant speed v around a circle of radius R if the pendulum undergoes small oscillation about it's equilibrium position it's frequency is?.
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