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An OPAMP has a slew rate of 5 V/μs. The largest sinewave output voltage possible at a frequency of 1 MHz is
  • a)
    10 π volts
  • b)
    5 volts
  • c)
    5/π volts
  • d)
    5/2π volts
Correct answer is option 'D'. Can you explain this answer?
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An OPAMP has a slew rate of 5 V/μs. The largest sinewave output vol...
V = Vm sin ωt
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An OPAMP has a slew rate of 5 V/μs. The largest sinewave output vol...
V = Vm sin ωt
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An OPAMP has a slew rate of 5 V/μs. The largest sinewave output vol...
S. This means that the output voltage of the OPAMP can change at a maximum rate of 5 volts per second. A slew rate is a measure of how quickly an OPAMP can respond to changes in the input signal. It is typically specified in volts per second (V/s) or volts per microsecond (V/μs).

In practical terms, a higher slew rate means that the OPAMP can handle faster changes in the input signal without distortion. For example, if the input signal changes rapidly, the OPAMP needs to be able to follow that change accurately in order to provide a faithful reproduction of the signal at the output.

In the case of a slew rate of 5 V/s, this means that the output voltage of the OPAMP can change by a maximum of 5 volts in one second. If the input signal changes at a faster rate, the OPAMP may not be able to keep up and the output signal may be distorted.

It is important to consider the slew rate when choosing an OPAMP for a particular application. If the input signal has fast transients or high-frequency components, a higher slew rate OPAMP may be required to ensure accurate signal reproduction.
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An OPAMP has a slew rate of 5 V/μs. The largest sinewave output voltage possible at a frequency of 1 MHz isa)10 πvoltsb)5voltsc)5/πvoltsd)5/2πvoltsCorrect answer is option 'D'. Can you explain this answer?
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