A contractor undertakes to make a mall in 60 days and he employs 30 me...
Let total work is w and it is given that one-third of the work is completed after 30 days. Means
M*D = 30*30 = w/3, so total work = 30*30*3
2700 = 30*30 + (30+p)*30, so we get P = 30 (p = additional men)
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A contractor undertakes to make a mall in 60 days and he employs 30 me...
Given:
- Time required to complete the mall = 60 days
- Number of men employed initially = 30
- Work completed in the first 30 days = 1/3
To complete the remaining 2/3 of the work in the remaining 30 days, the contractor would need to increase the workforce. Let's assume that the number of extra men required is x.
Workforce required to complete the remaining 2/3 of the work:
- In the first 30 days, 1/3 of the work is completed by 30 men
- So, the remaining 2/3 of the work would require the same 30 men and additional x men
- Total workforce required = 30 + x
Now, we can use the concept of work done to find the value of x.
Work done = (Number of men) x (Time taken)
As the work to be done is the same, we can equate the left-hand side of the equation for the first 30 days and the remaining 30 days.
Work done in the first 30 days = Work done in the remaining 30 days
(30 men) x (30 days) x (1/3) = (30 + x men) x (30 days) x (2/3)
Solving this equation, we get:
x = 30 men
Therefore, the contractor would need to employ an additional 30 men to complete the work on time. Hence, the correct answer is option C.