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x² + 32x + 247 = 0
y² + 20y + 91 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X &...
Quadratic Equations:
The given equations are quadratic equations in the form ax^2 + bx + c = 0 and ay^2 + by + c = 0. We need to compare the roots of these equations, denoted by X and Y.
Finding the Roots:
To find the roots of the equation x^2 + 32x + 247 = 0, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. By substituting a = 1, b = 32, and c = 247 into the formula, we find the roots of this equation.
Similarly, for the equation y^2 + 20y + 91 = 0, we can find the roots using the quadratic formula with a = 1, b = 20, and c = 91.
Comparing the Roots:
After finding the roots for both equations, we can compare them to determine the relationship between X and Y.
In this case, if the roots of the equation x^2 + 32x + 247 = 0 are less than or equal to the roots of y^2 + 20y + 91 = 0, then we have X ≤ Y. Therefore, the correct answer is option 'D' which states that X is less than or equal to Y.
Conclusion:
By comparing the roots of the given quadratic equations, we can establish the relationship between X and Y. In this case, X is less than or equal to Y, as determined by the roots of the equations.
The given equations are quadratic equations in the form ax^2 + bx + c = 0 and ay^2 + by + c = 0. We need to compare the roots of these equations, denoted by X and Y.
Finding the Roots:
To find the roots of the equation x^2 + 32x + 247 = 0, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. By substituting a = 1, b = 32, and c = 247 into the formula, we find the roots of this equation.
Similarly, for the equation y^2 + 20y + 91 = 0, we can find the roots using the quadratic formula with a = 1, b = 20, and c = 91.
Comparing the Roots:
After finding the roots for both equations, we can compare them to determine the relationship between X and Y.
In this case, if the roots of the equation x^2 + 32x + 247 = 0 are less than or equal to the roots of y^2 + 20y + 91 = 0, then we have X ≤ Y. Therefore, the correct answer is option 'D' which states that X is less than or equal to Y.
Conclusion:
By comparing the roots of the given quadratic equations, we can establish the relationship between X and Y. In this case, X is less than or equal to Y, as determined by the roots of the equations.
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Community Answer
x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X &...
x� + 32x + 247 = 0
x = -13, -19
y� + 20y + 91 = 0
y = -13, -7
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x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'D'. Can you explain this answer?
Question Description
x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'D'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for x² + 32x + 247 = 0y² + 20y + 91 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'D'. Can you explain this answer?.
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