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3x² + 20x + 33 = 0
2y² – 13y + 21 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
3x² + 20x + 33 = 02y² – 13y + 21 = 0a)X > Yb)X <...
3x² + 20x + 33 = 0
x = -3.6, -3
2y² – 13y + 21 = 0
y = 3, 3.5
x = -3.6, -3
2y² – 13y + 21 = 0
y = 3, 3.5
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Community Answer
3x² + 20x + 33 = 02y² – 13y + 21 = 0a)X > Yb)X <...
Given equation:
3x^2 + 20x + 33 = 0
2y^2 - 13y + 21 = 0
Analysis:
To determine the relationship between x and y, we need to solve the given equations to find the values of x and y.
Solving the first equation:
3x^2 + 20x + 33 = 0
(x + 3)(3x + 11) = 0
x = -3 or x = -11/3
Solving the second equation:
2y^2 - 13y + 21 = 0
(y - 3)(2y - 7) = 0
y = 3 or y = 7/2
Comparison:
x can take values -3 or -11/3, while y can take values 3 or 7/2.
Since -3 is less than 3 and -11/3 is less than 7/2, we can conclude that x < />
Therefore, the correct answer is option B) X < />.
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3x² + 20x + 33 = 02y² – 13y + 21 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?
Question Description
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