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The average salary of the entire staff in an office is Rs 250 per month. The average salary of officers is Rs 520 and that of non-officers is Rs. 200.
Quantity I: Number of Officers = 15
Quantity II: Number of Non-Officers
Quantity II: Number of Non-Officers
- a)Quantity I > Quantity II
- b)Quantity I < Quantity II
- c)Quantity I ≥ Quantity II
- d)Quantity I ≤ Quantity II
- e)Quantity I = Quantity II or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The average salary of the entire staff in an office is Rs 250 per mont...
Let the required number of non–officers = x
200x + 520 x 15 = 250 (15 + x)
250x – 200x = 520 * 15 – 250 x 15
50x = 4050
x = 81
200x + 520 x 15 = 250 (15 + x)
250x – 200x = 520 * 15 – 250 x 15
50x = 4050
x = 81
Most Upvoted Answer
The average salary of the entire staff in an office is Rs 250 per mont...
Understanding the Problem:
The problem states that the average salary of the entire staff in an office is Rs 250 per month, with officers earning an average of Rs 520 and non-officers earning an average of Rs 200.
Calculating the Average:
Let the number of officers be \( x \) and the number of non-officers be \( y \).
Based on the given information, we can create the following equations:
1. \( 520x + 200y = 250(x + y) \) (since the average salary of the entire staff is Rs 250)
2. \( x + y = Total Staff \)
Solving these equations, we get:
\( 270x = 50y \)
\( x = 5y/27 \)
Comparing Quantity I and Quantity II:
Quantity I: Number of Officers = 15
Quantity II: Number of Non-Officers
If we substitute the value of officers in terms of non-officers from our calculation above into Quantity I, we get:
\( 5y/27 = 15 \)
\( y = 81 \)
Hence, the number of non-officers is 81. Therefore, Quantity II is greater than Quantity I as the number of non-officers is 81, which is greater than 15 (number of officers).
Therefore, the correct answer is option B.
The problem states that the average salary of the entire staff in an office is Rs 250 per month, with officers earning an average of Rs 520 and non-officers earning an average of Rs 200.
Calculating the Average:
Let the number of officers be \( x \) and the number of non-officers be \( y \).
Based on the given information, we can create the following equations:
1. \( 520x + 200y = 250(x + y) \) (since the average salary of the entire staff is Rs 250)
2. \( x + y = Total Staff \)
Solving these equations, we get:
\( 270x = 50y \)
\( x = 5y/27 \)
Comparing Quantity I and Quantity II:
Quantity I: Number of Officers = 15
Quantity II: Number of Non-Officers
If we substitute the value of officers in terms of non-officers from our calculation above into Quantity I, we get:
\( 5y/27 = 15 \)
\( y = 81 \)
Hence, the number of non-officers is 81. Therefore, Quantity II is greater than Quantity I as the number of non-officers is 81, which is greater than 15 (number of officers).
Therefore, the correct answer is option B.
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The average salary of the entire staff in an office is Rs 250 per month. The average salary of officers is Rs 520 and that of non-officers is Rs. 200.Quantity I: Number of Officers = 15Quantity II: Number of Non-Officersa)Quantity I > Quantity IIb)Quantity I < Quantity IIc)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?
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