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x² – 28x + 195 = 0
y² – 30y + 216 = 0
  • a)
    X > Y
  • b)
    X < Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relation cannot be established
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
x² – 28x + 195 = 0y² – 30y + 216 = 0a)X > Yb)...
x² – 28x + 195 = 0
x = 15, 13
y² – 30y + 216 = 0
y = 18, 12
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Most Upvoted Answer
x² – 28x + 195 = 0y² – 30y + 216 = 0a)X > Yb)...
Factor of 195& 216
195= 3*5*13, pair of 28 will be= -15&-13, X=13&15
216=2*2*2*3*3*3, pair of 28 will be = -12&-18, Y= 12&18
value can't be established.. once time X can be greater & 2nd time will smaller same as Y... so (e)
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x² – 28x + 195 = 0y² – 30y + 216 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'E'. Can you explain this answer?
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