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x² – 41x + 400 = 0
y² – 29y + 210 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
x² – 41x + 400 = 0y² – 29y + 210 = 0a)X > Yb)...
Understanding the Quadratic Equations
To determine the relationship between X and Y, we first need to solve the two quadratic equations given:
1. Equation for X:
- x² - 41x + 400 = 0
2. Equation for Y:
- y² - 29y + 210 = 0
Solving for X
- Utilize the quadratic formula: x = [−b ± sqrt(b² - 4ac)] / 2a
- Here, a = 1, b = -41, and c = 400.
- Calculate the discriminant:
- Discriminant = b² - 4ac = 41² - 4(1)(400) = 1681 - 1600 = 81
- Find the roots:
- x = [41 ± sqrt(81)] / 2 = [41 ± 9] / 2
- Roots are:
- x1 = (41 + 9) / 2 = 25
- x2 = (41 - 9) / 2 = 16
- Thus, X can be either 25 or 16.
Solving for Y
- Similarly, apply the quadratic formula:
- Here, a = 1, b = -29, and c = 210.
- Calculate the discriminant:
- Discriminant = b² - 4ac = 29² - 4(1)(210) = 841 - 840 = 1
- Find the roots:
- y = [29 ± sqrt(1)] / 2 = [29 ± 1] / 2
- Roots are:
- y1 = (29 + 1) / 2 = 15
- y2 = (29 - 1) / 2 = 14
- Thus, Y can be either 15 or 14.
Comparing X and Y
- Possible values for X: 25, 16
- Possible values for Y: 15, 14
- The largest value of X (25) is greater than the largest value of Y (15).
Conclusion
- Therefore, the relation established is X > Y, confirming option 'A' as the correct answer.
To determine the relationship between X and Y, we first need to solve the two quadratic equations given:
1. Equation for X:
- x² - 41x + 400 = 0
2. Equation for Y:
- y² - 29y + 210 = 0
Solving for X
- Utilize the quadratic formula: x = [−b ± sqrt(b² - 4ac)] / 2a
- Here, a = 1, b = -41, and c = 400.
- Calculate the discriminant:
- Discriminant = b² - 4ac = 41² - 4(1)(400) = 1681 - 1600 = 81
- Find the roots:
- x = [41 ± sqrt(81)] / 2 = [41 ± 9] / 2
- Roots are:
- x1 = (41 + 9) / 2 = 25
- x2 = (41 - 9) / 2 = 16
- Thus, X can be either 25 or 16.
Solving for Y
- Similarly, apply the quadratic formula:
- Here, a = 1, b = -29, and c = 210.
- Calculate the discriminant:
- Discriminant = b² - 4ac = 29² - 4(1)(210) = 841 - 840 = 1
- Find the roots:
- y = [29 ± sqrt(1)] / 2 = [29 ± 1] / 2
- Roots are:
- y1 = (29 + 1) / 2 = 15
- y2 = (29 - 1) / 2 = 14
- Thus, Y can be either 15 or 14.
Comparing X and Y
- Possible values for X: 25, 16
- Possible values for Y: 15, 14
- The largest value of X (25) is greater than the largest value of Y (15).
Conclusion
- Therefore, the relation established is X > Y, confirming option 'A' as the correct answer.
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Community Answer
x² – 41x + 400 = 0y² – 29y + 210 = 0a)X > Yb)...
x² – 41x + 400 = 0
x = 25, 16
y² – 29y + 210 = 0
y = 14, 15
x = 25, 16
y² – 29y + 210 = 0
y = 14, 15
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x² – 41x + 400 = 0y² – 29y + 210 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'A'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about x² – 41x + 400 = 0y² – 29y + 210 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for x² – 41x + 400 = 0y² – 29y + 210 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'A'. Can you explain this answer?.
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