Quant Exam > Quant Questions > x² = 121y² – 46y + 529 = 0a)X...
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x² = 121
y² – 46y + 529 = 0
- a)X > Y
- b)X < Y
- c)X ≥ Y
- d)X ≤ Y
- e)X = Y or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
x² = 121y² – 46y + 529 = 0a)X > Yb)X < Yc)X ≥...
Analysis:
The given equation is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -46, and c = 529.
Discriminant:
The discriminant of a quadratic equation is given by the formula Δ = b^2 - 4ac. If Δ > 0, the equation has two distinct real roots. If Δ = 0, the equation has one real root. If Δ < 0,="" the="" equation="" has="" no="" real="" />
Calculating Discriminant:
Δ = (-46)^2 - 4*1*529
Δ = 2116 - 2116
Δ = 0
Conclusion:
Since the discriminant is equal to zero, the equation has one real root. This means that X = Y.
Therefore, the correct answer is option 'B' which states that X < y.="" />
The given equation is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -46, and c = 529.
Discriminant:
The discriminant of a quadratic equation is given by the formula Δ = b^2 - 4ac. If Δ > 0, the equation has two distinct real roots. If Δ = 0, the equation has one real root. If Δ < 0,="" the="" equation="" has="" no="" real="" />
Calculating Discriminant:
Δ = (-46)^2 - 4*1*529
Δ = 2116 - 2116
Δ = 0
Conclusion:
Since the discriminant is equal to zero, the equation has one real root. This means that X = Y.
Therefore, the correct answer is option 'B' which states that X < y.="" />
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Community Answer
x² = 121y² – 46y + 529 = 0a)X > Yb)X < Yc)X ≥...
x² = 121
x = 11, – 11
y² – 46y + 529 = 0
y = 23, 23
x = 11, – 11
y² – 46y + 529 = 0
y = 23, 23
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x² = 121y² – 46y + 529 = 0a)X > Yb)X < Yc)X ≥ Yd)X ≤ Ye)X = Y or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?
Question Description
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