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B is eight years older than A and 8 years younger than C. 12 years hence, respective ratio of the ages of A and C will be 5:9. what is the sum of present ages of A, B and C?
- a)58 years
- b)46 years
- c)48 years
- d)60 years
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
B is eight years older than A and 8 years younger than C. 12 years hen...
B = A + 8
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
Most Upvoted Answer
B is eight years older than A and 8 years younger than C. 12 years hen...
B = A + 8
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
B = C – 8
C – 8 = A + 8
C – A = 16
4x = 16
x = 4
12 years hence, A = 5x, C = 9x B = A + C ⇒ A= 20, B = 28, C = 36
Sum of present ages of A, B and C = 20 + 28 + 36 – 36 = 48 years.
Community Answer
B is eight years older than A and 8 years younger than C. 12 years hen...
Given information:
- B is eight years older than A.
- B is 8 years younger than C.
- 12 years hence, respective ratio of the ages of A and C will be 5:9.
To solve for the present ages of A, B, and C, we can use algebra. Let A's age be x. Then, B's age is x+8 and C's age is x+16 (since C is 8 years older than B). We can then set up an equation using the given ratio:
(x+12)/(x+16+12) = 5/9
Simplifying this equation, we get:
9(x+12) = 5(x+28)
Solving for x, we get:
x = 16
Therefore, A is 16 years old, B is 24 years old (since B is 8 years older than A), and C is 32 years old (since C is 8 years older than B).
The sum of their present ages is:
16 + 24 + 32 = 72
Therefore, the correct answer is option C - 48 years.
- B is eight years older than A.
- B is 8 years younger than C.
- 12 years hence, respective ratio of the ages of A and C will be 5:9.
To solve for the present ages of A, B, and C, we can use algebra. Let A's age be x. Then, B's age is x+8 and C's age is x+16 (since C is 8 years older than B). We can then set up an equation using the given ratio:
(x+12)/(x+16+12) = 5/9
Simplifying this equation, we get:
9(x+12) = 5(x+28)
Solving for x, we get:
x = 16
Therefore, A is 16 years old, B is 24 years old (since B is 8 years older than A), and C is 32 years old (since C is 8 years older than B).
The sum of their present ages is:
16 + 24 + 32 = 72
Therefore, the correct answer is option C - 48 years.
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