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An ideal gas heat engine operates in Carnot cycle between 227ºC and 127ºC. It absorbs 6 x 104 cals of heat at higher temp. Amount of heat converted into work is
  • a)
    1.2 x 104 cals
  • b)
    2.4 x 104 cals
  • c)
    6 x 104 cals
  • d)
    4.8 x 104 cals
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An ideal gas heat engine operates in Carnot cycle between 227ºC a...

 = 4.8 x 104 cals
∴ W = Q1 - Q2 = 6 x 104 - 4.8 x 104
= 1.2 x 104 cals
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Most Upvoted Answer
An ideal gas heat engine operates in Carnot cycle between 227ºC a...
The Carnot cycle is a theoretical thermodynamic cycle that consists of four processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. In order to fully describe the operation of the ideal gas heat engine in the Carnot cycle, we need to know the temperatures of the two heat reservoirs between which the engine operates.

Let's assume that the lower temperature reservoir is at 227 K (Kelvin). We need to determine the temperature of the higher temperature reservoir.

In the Carnot cycle, the isothermal expansion process occurs at the higher temperature reservoir, and the isothermal compression process occurs at the lower temperature reservoir.

During the isothermal expansion, the gas absorbs heat Q1 from the higher temperature reservoir and expands, doing work on the surroundings. The temperature of the gas during this process is equal to the temperature of the higher temperature reservoir.

During the adiabatic expansion, the gas continues to expand without exchanging heat with the surroundings. This process decreases the temperature of the gas.

During the isothermal compression, the gas releases heat Q2 to the lower temperature reservoir and compresses. The temperature of the gas during this process is equal to the temperature of the lower temperature reservoir.

During the adiabatic compression, the gas continues to compress without exchanging heat with the surroundings. This process increases the temperature of the gas back to the initial temperature.

Since the engine operates in a Carnot cycle, the efficiency of the engine is given by:

Efficiency = 1 - (T2 / T1)

where T2 is the temperature of the lower temperature reservoir and T1 is the temperature of the higher temperature reservoir.

In this case, T2 = 227 K. To determine T1, we need to know the efficiency of the engine.

Please provide the efficiency of the engine, and I can calculate the temperature of the higher temperature reservoir (T1).
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An ideal gas heat engine operates in Carnot cycle between 227ºC and 127ºC. It absorbs 6 x104 cals of heat at higher temp. Amount of heat converted into work isa)1.2 x 104 calsb)2.4 x 104 calsc)6 x 104 calsd)4.8 x 104 calsCorrect answer is option 'A'. Can you explain this answer?
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