Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is...
Square numbers – a, b, c
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
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Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is...
Square numbers – a, b, c
(a + 5) + (b + 5)+ (c + 5) = 44
a + b + c = 44 – 15 = 29
Possible values of a, b, c = 4, 9, 16 [Out of 1, 4, 9, 16, 25] Ramya’s present age = 16; after two years = 18
Mr. Suresh has three daughters namely Ramya, Anita and Kiran. Ramya is...
Given information:
- Mr. Suresh has three daughters named Ramya, Anita, and Kiran.
- Ramya is the eldest daughter, and Kiran is the youngest one.
- The present ages of all three of them are square numbers.
- The sum of their ages after 5 years is 44.
To find:
- The age of Ramya after two years.
Solution:
Let's assume the present age of Ramya, Anita, and Kiran as x, y, and z, respectively.
According to the given information, x, y, and z are all square numbers. Therefore, we can write:
x = a^2
y = b^2
z = c^2
where a, b, and c are integers.
Now, the sum of their ages after 5 years can be written as:
(x+5) + (y+5) + (z+5) = 44
Substituting the values of x, y, and z, we get:
(a^2+5) + (b^2+5) + (c^2+5) = 44
a^2 + b^2 + c^2 + 15 = 44
a^2 + b^2 + c^2 = 29
As a, b, and c are integers, we can see that the only possible values for a, b, and c are 1, 2, and 3 (since 4^2 > 29).
Therefore, the possible ages of Ramya, Anita, and Kiran are:
Ramya: a^2 = 1^2 = 1
Anita: b^2 = 2^2 = 4
Kiran: c^2 = 3^2 = 9
So, Ramya is currently 1^2 = 1 year old.
To find her age after two years, we add 2 to her current age:
Ramya's age after 2 years = 1 + 2 = 3 years
Therefore, the correct option is (c) 18 years.