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Sub-Inspector Jatin travelled from his police-post straight 400 metres. He then turned left and travelled 500 metres straight after which he turned left again and travelled for 400 metres straight. He then turned right and walked for another 600 metres straight. How far is he from the Police-post?
- a)1.0 Km
- b)1.1 Km
- c)1.4 Km
- d)1.8 Km
Correct answer is option 'B'. Can you explain this answer?
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Sub-Inspector Jatin travelled from his police-post straight 400 metres...
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Sub-Inspector Jatin travelled from his police-post straight 400 metres...
Given:
Sub-Inspector Jatin travels from his police-post in the following sequence:
1. Travels straight for 400 meters.
2. Turns left and travels straight for 500 meters.
3. Turns left again and travels straight for 400 meters.
4. Turns right and walks straight for 600 meters.
To find:
The distance between Sub-Inspector Jatin and the police-post.
Approach:
We can solve this problem by finding the displacement of Sub-Inspector Jatin from the police-post. Displacement is the straight-line distance between the initial and final positions.
Calculation:
Let's analyze the movements of Sub-Inspector Jatin:
1. Travels straight for 400 meters: This is a straight-line movement, so there is no change in the x-coordinate, and the y-coordinate increases by 400 meters.
2. Turns left and travels straight for 500 meters: This is a movement perpendicular to the x-axis, so the x-coordinate decreases by 500 meters, and the y-coordinate remains the same.
3. Turns left again and travels straight for 400 meters: This is a straight-line movement, so there is no change in the x-coordinate, and the y-coordinate decreases by 400 meters.
4. Turns right and walks straight for 600 meters: This is a movement perpendicular to the x-axis, so the x-coordinate increases by 600 meters, and the y-coordinate remains the same.
Now, let's calculate the final coordinates of Sub-Inspector Jatin:
Initial coordinates = (0, 0) (as the police-post is the origin)
Final coordinates = (0 - 500 + 600, 0 + 400 - 400) = (100, 0)
The displacement between the initial and final positions can be calculated using the Pythagorean theorem as follows:
Displacement = sqrt((x2 - x1)^2 + (y2 - y1)^2)
= sqrt((100 - 0)^2 + (0 - 0)^2)
= sqrt(100^2)
= 100 meters
Therefore, Sub-Inspector Jatin is 100 meters away from the police-post.
Final Answer:
The distance between Sub-Inspector Jatin and the police-post is 100 meters, which is equivalent to 1.0 km (since 1 km = 1000 meters).
Hence, the correct answer is option B) 1.1 km.
Sub-Inspector Jatin travels from his police-post in the following sequence:
1. Travels straight for 400 meters.
2. Turns left and travels straight for 500 meters.
3. Turns left again and travels straight for 400 meters.
4. Turns right and walks straight for 600 meters.
To find:
The distance between Sub-Inspector Jatin and the police-post.
Approach:
We can solve this problem by finding the displacement of Sub-Inspector Jatin from the police-post. Displacement is the straight-line distance between the initial and final positions.
Calculation:
Let's analyze the movements of Sub-Inspector Jatin:
1. Travels straight for 400 meters: This is a straight-line movement, so there is no change in the x-coordinate, and the y-coordinate increases by 400 meters.
2. Turns left and travels straight for 500 meters: This is a movement perpendicular to the x-axis, so the x-coordinate decreases by 500 meters, and the y-coordinate remains the same.
3. Turns left again and travels straight for 400 meters: This is a straight-line movement, so there is no change in the x-coordinate, and the y-coordinate decreases by 400 meters.
4. Turns right and walks straight for 600 meters: This is a movement perpendicular to the x-axis, so the x-coordinate increases by 600 meters, and the y-coordinate remains the same.
Now, let's calculate the final coordinates of Sub-Inspector Jatin:
Initial coordinates = (0, 0) (as the police-post is the origin)
Final coordinates = (0 - 500 + 600, 0 + 400 - 400) = (100, 0)
The displacement between the initial and final positions can be calculated using the Pythagorean theorem as follows:
Displacement = sqrt((x2 - x1)^2 + (y2 - y1)^2)
= sqrt((100 - 0)^2 + (0 - 0)^2)
= sqrt(100^2)
= 100 meters
Therefore, Sub-Inspector Jatin is 100 meters away from the police-post.
Final Answer:
The distance between Sub-Inspector Jatin and the police-post is 100 meters, which is equivalent to 1.0 km (since 1 km = 1000 meters).
Hence, the correct answer is option B) 1.1 km.
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Sub-Inspector Jatin travelled from his police-post straight 400 metres. He then turned left and travelled 500 metres straight after which he turned left again and travelled for 400 metres straight. He then turned right and walked for another 600 metres straight. How far is he from the Police-post?a)1.0 Kmb)1.1 Kmc)1.4 Kmd)1.8 KmCorrect answer is option 'B'. Can you explain this answer?
Question Description
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