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The fundamental band for CO is centered at 2143 cm-1 and the first overtone at 4259.7 cm-1. The value of anhannonicity constant is ________.
(Upto three decimal places)
    Correct answer is between '0.004,0.008'. Can you explain this answer?
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    Calculation of Anharmonicity Constant for CO Molecule

    Fundamental Band and First Overtone of CO Molecule

    - The fundamental band of CO molecule is centered at 2143 cm-1.
    - The first overtone of CO molecule is located at 4259.7 cm-1.

    Formula for Anharmonicity Constant

    - The anharmonicity constant of a molecule can be calculated using the following formula:

    ωeχe = ωexe - ωey

    where,
    ωe = vibrational energy of the molecule in the ground state
    ωexe = vibrational energy of the molecule in the excited state
    ωey = vibrational energy of the molecule in the electronically excited state
    χe = anharmonicity constant

    Calculation of Anharmonicity Constant for CO Molecule

    - The vibrational energy of the fundamental band of CO molecule is given by:

    ωe = 2143 cm-1

    - The vibrational energy of the first overtone of CO molecule is given by:

    ωexe = 4259.7 cm-1

    - The electronically excited state of CO molecule is not considered in this calculation.
    - Substituting the values in the formula, we get:

    2143χe = 4259.7 - 2143

    χe = (4259.7 - 2143)/2143

    χe = 0.988

    - The anharmonicity constant of CO molecule is 0.988.
    - The correct answer is between 0.004 and 0.008, which is not the calculated value.
    - It is possible that the question requires the anharmonicity constant in different units or requires a different method of calculation.
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    The fundamental band for CO is centered at 2143 cm-1 and the first overtone at 4259.7 cm-1. The value of anhannonicity constant is ________.(Upto three decimal places)Correct answer is between '0.004,0.008'. Can you explain this answer?
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