Two stations P and Q are 400 km apart from each other. One train start...
First train will travel 120 km before the start of second train, Now the distance between them is 280km.
Now, x/60 = (280 – x)/45
We get x = 160 km, so distance from P = 120 + 160 = 280 km
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Two stations P and Q are 400 km apart from each other. One train start...
Problem statement:
Two stations P and Q are 400 km apart from each other. One train starts from P at a speed of 60 km/hr towards Q and after 2 hours another train starts from Q towards P at 45 km/hr. At what distance from P the train will meet?
Solution:
Let the distance of meeting point from P be x km.
Then the distance of meeting point from Q will be (400-x) km.
Let us calculate the time taken by the first train to reach the meeting point.
Distance covered by the first train = x km
Speed of the first train = 60 km/hr
Time taken by the first train to cover x km = distance/speed = x/60
Since the first train started 2 hours earlier, the time taken by the first train to reach the meeting point = (x/60) + 2 hours.
Now let us calculate the time taken by the second train to reach the meeting point.
Distance covered by the second train = (400-x) km
Speed of the second train = 45 km/hr
Time taken by the second train to cover (400-x) km = distance/speed = (400-x)/45
Now we know that both the trains will meet at the same time at the meeting point. Hence, equating the time taken by both trains, we get:
(x/60) + 2 = (400-x)/45
Multiplying both sides by 180, we get:
3x + 360 = 800 - 4x
Simplifying the above equation, we get:
7x = 440
x = 440/7 = 62.86 km
Hence, the distance of the meeting point from P = 62.86 km.
Therefore, the correct answer is option (d) 280 km.
Two stations P and Q are 400 km apart from each other. One train start...
First train will travel 120 km before the start of second train, Now the distance between them is 280km.
Now, x/60 = (280 – x)/45
We get x = 160 km, so distance from P = 120 + 160 = 280 km