Two stations A and B are 150 km apart from each other. One train start...
Distance travel by first train in one hour = 30, now the distance remains 120 km only.
x/30 = (120 – x)/20, so we get x = 72 km
Now, time = (30 + 72)/30 = 3hrs and 24minutes i.e. 9: 34 am
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Two stations A and B are 150 km apart from each other. One train start...
Problem Statement:
Two stations A and B are 150 km apart from each other. One train starts from A at 6 AM at a speed of 30 km/hr and travels towards B. Another train starts from station B at 7 AM at a speed of 20 km/hr. At what time they will meet.
Solution:
Let us first calculate the distance covered by the first train in one hour. As the speed of the first train is 30 km/hr, it will cover 30 km in one hour.
Now, let us assume that the two trains meet after t hours. Therefore, the second train would have traveled for (t-1) hours before they meet. As the speed of the second train is 20 km/hr, it would have covered 20(t-1) km before they meet.
Also, the total distance between the two stations is 150 km. Therefore, the distance covered by the first train in t hours is 30t km.
As the two trains meet, the total distance covered by both the trains is 150 km. Therefore, we can write the equation:
30t + 20(t-1) = 150
Simplifying the above equation, we get:
50t - 20 = 150
50t = 170
t = 3.4
Therefore, the two trains will meet after 3.4 hours from the time the first train started, which is 6 AM.
So, the time at which the two trains will meet is:
6 AM + 3 hours and 24 minutes = 9:24 AM
Hence, the correct option is A) 9:34 AM.
Two stations A and B are 150 km apart from each other. One train start...
Distance travel by first train in one hour = 30, now the distance remains 120 km only.
x/30 = (120 – x)/20, so we get x = 72 km
Now, time = (30 + 72)/30 = 3hrs and 24minutes i.e. 9: 34 am