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A bus was travelling from Mumbai to Pune was delayed by 16 minutes and made up for the delay on a section of 80 km travelling with a speed 10 km per hour higher than its normal speed. Find the original speed of the bus?
- a)60 km/h
- b)66.66 km/h
- c)50 km/h
- d)40 km/h
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A bus was travelling from Mumbai to Pune was delayed by 16 minutes and...
80/x – 80/(x+10) = 16/60= 4/15
300/x -300/x+10 =1
X2 + 10x – 3000 = 0
X = -60, +50
So 50km/hr
300/x -300/x+10 =1
X2 + 10x – 3000 = 0
X = -60, +50
So 50km/hr
This question is part of UPSC exam. View all Quant courses
Most Upvoted Answer
A bus was travelling from Mumbai to Pune was delayed by 16 minutes and...
To solve this problem, we can use the formula:
Time = Distance / Speed
Let's assume the original speed of the bus is 's' km/h.
1. Calculating the time taken without delay:
The distance between Mumbai and Pune is 80 km. So, the time taken to cover this distance without delay can be calculated using the formula as follows:
Time taken = Distance / Speed = 80 / s
2. Calculating the time taken with delay:
The bus was delayed by 16 minutes, which is equal to 16/60 = 4/15 hours. So, the time taken to cover the same distance with the delay can be calculated as follows:
Time taken = Distance / (Speed + 10) = 80 / (s + 10)
3. Equating the two time values:
Since the bus made up for the delay on a section of 80 km, the time taken to cover this distance with and without delay should be equal. Therefore, we can equate the two time values obtained in steps 1 and 2:
80 / s = 80 / (s + 10)
4. Solving the equation:
To solve the equation, we can cross multiply and simplify:
80(s + 10) = 80s
80s + 800 = 80s
800 = 80s - 80s
800 = 0
This equation has no solution, which means there is an error in the given options. The correct answer cannot be determined based on the information provided in the question.
Therefore, the correct answer is e) None of these.
Time = Distance / Speed
Let's assume the original speed of the bus is 's' km/h.
1. Calculating the time taken without delay:
The distance between Mumbai and Pune is 80 km. So, the time taken to cover this distance without delay can be calculated using the formula as follows:
Time taken = Distance / Speed = 80 / s
2. Calculating the time taken with delay:
The bus was delayed by 16 minutes, which is equal to 16/60 = 4/15 hours. So, the time taken to cover the same distance with the delay can be calculated as follows:
Time taken = Distance / (Speed + 10) = 80 / (s + 10)
3. Equating the two time values:
Since the bus made up for the delay on a section of 80 km, the time taken to cover this distance with and without delay should be equal. Therefore, we can equate the two time values obtained in steps 1 and 2:
80 / s = 80 / (s + 10)
4. Solving the equation:
To solve the equation, we can cross multiply and simplify:
80(s + 10) = 80s
80s + 800 = 80s
800 = 80s - 80s
800 = 0
This equation has no solution, which means there is an error in the given options. The correct answer cannot be determined based on the information provided in the question.
Therefore, the correct answer is e) None of these.
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A bus was travelling from Mumbai to Pune was delayed by 16 minutes and made up for the delay on a section of 80 km travelling with a speed 10 km per hour higher than its normal speed. Find the original speed of the bus?a)60 km/hb)66.66 km/hc)50 km/hd)40 km/he)None of theseCorrect answer is option 'C'. Can you explain this answer?
Question Description
A bus was travelling from Mumbai to Pune was delayed by 16 minutes and made up for the delay on a section of 80 km travelling with a speed 10 km per hour higher than its normal speed. Find the original speed of the bus?a)60 km/hb)66.66 km/hc)50 km/hd)40 km/he)None of theseCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A bus was travelling from Mumbai to Pune was delayed by 16 minutes and made up for the delay on a section of 80 km travelling with a speed 10 km per hour higher than its normal speed. Find the original speed of the bus?a)60 km/hb)66.66 km/hc)50 km/hd)40 km/he)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bus was travelling from Mumbai to Pune was delayed by 16 minutes and made up for the delay on a section of 80 km travelling with a speed 10 km per hour higher than its normal speed. Find the original speed of the bus?a)60 km/hb)66.66 km/hc)50 km/hd)40 km/he)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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