Quant Exam > Quant Questions > A car after travelling 100 km from point A me...
Start Learning for Free
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?
- a)60km/hr
- b)80km/hr
- c)100km/hr
- d)120km/hr
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A car after travelling 100 km from point A meets with an accident and ...
let distance between A and B be D km and real speed of the car be S km/hr
First time car takes 90 minutes more and second time car takes 75 minutes more than scheduled time.
So, T1 – T2 = 15/60 = 100
15/60 = [100/s + (D -100)/(3s/4)] – [160/s + (D – 160)/(3s/4)] Solve this D will be cancelled and S comes out to be 80km/hr
First time car takes 90 minutes more and second time car takes 75 minutes more than scheduled time.
So, T1 – T2 = 15/60 = 100
15/60 = [100/s + (D -100)/(3s/4)] – [160/s + (D – 160)/(3s/4)] Solve this D will be cancelled and S comes out to be 80km/hr
Most Upvoted Answer
A car after travelling 100 km from point A meets with an accident and ...
To solve this problem, let's go step by step:
1. Let's assume the original speed of the car as 'S' km/hr.
2. According to the given information, the car traveled 100 km from point A before meeting with an accident. Let's denote the time taken for this distance as 't' hours.
3. Using the formula: Speed = Distance/Time, we can write the equation as:
S = 100/t
4. After the accident, the car proceeds at 3/4 of its original speed. So, the new speed becomes (3/4)S km/hr.
5. The car arrives at point B 90 minutes late, which is equal to 1.5 hours. Let's denote the total time taken to reach point B as 'T' hours.
6. The distance between the accident spot and point B can be calculated as:
Distance = Total distance - Distance traveled before the accident
Distance = 100 + 60 = 160 km
7. Using the formula: Speed = Distance/Time, we can write the equation as:
(3/4)S = 160/(T - t)
8. Given that if the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Let's denote the new distance between the accident spot and point B as 'D' km.
9. Using the formula: Speed = Distance/Time, we can write the equation as:
(3/4)S = D/(T - t - 1/4)
10. We can simplify the above equations and form a system of equations to solve for 'S' and 'T':
S = 100/t
(3/4)S = 160/(T - t)
(3/4)S = D/(T - t - 1/4)
11. By substituting the value of S from the first equation into the second and third equations, we get:
(3/4)(100/t) = 160/(T - t)
(3/4)(100/t) = D/(T - t - 1/4)
12. Simplifying the above equations, we get:
300/t = 160/(T - t)
300/t = D/(T - t - 1/4)
13. Cross-multiplying the above equations, we get:
300(T - t) = 160t
300(T - t - 1/4) = Dt
14. Expanding the equations, we get:
300T - 300t = 160t
300T - 300t - 75 = Dt
15. Simplifying further, we get:
300T = 460t
300T - 460t = 75
16. Dividing both equations, we get:
T/t = 23/15
17. Now, substituting the value of T/t into the first equation, we get:
300(23/15) = 460
23/5 = 460/300
23/5 = 23/5
18. Therefore, the original speed of the car (S) is 23/5 times the time taken (t) to travel 100 km from
1. Let's assume the original speed of the car as 'S' km/hr.
2. According to the given information, the car traveled 100 km from point A before meeting with an accident. Let's denote the time taken for this distance as 't' hours.
3. Using the formula: Speed = Distance/Time, we can write the equation as:
S = 100/t
4. After the accident, the car proceeds at 3/4 of its original speed. So, the new speed becomes (3/4)S km/hr.
5. The car arrives at point B 90 minutes late, which is equal to 1.5 hours. Let's denote the total time taken to reach point B as 'T' hours.
6. The distance between the accident spot and point B can be calculated as:
Distance = Total distance - Distance traveled before the accident
Distance = 100 + 60 = 160 km
7. Using the formula: Speed = Distance/Time, we can write the equation as:
(3/4)S = 160/(T - t)
8. Given that if the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Let's denote the new distance between the accident spot and point B as 'D' km.
9. Using the formula: Speed = Distance/Time, we can write the equation as:
(3/4)S = D/(T - t - 1/4)
10. We can simplify the above equations and form a system of equations to solve for 'S' and 'T':
S = 100/t
(3/4)S = 160/(T - t)
(3/4)S = D/(T - t - 1/4)
11. By substituting the value of S from the first equation into the second and third equations, we get:
(3/4)(100/t) = 160/(T - t)
(3/4)(100/t) = D/(T - t - 1/4)
12. Simplifying the above equations, we get:
300/t = 160/(T - t)
300/t = D/(T - t - 1/4)
13. Cross-multiplying the above equations, we get:
300(T - t) = 160t
300(T - t - 1/4) = Dt
14. Expanding the equations, we get:
300T - 300t = 160t
300T - 300t - 75 = Dt
15. Simplifying further, we get:
300T = 460t
300T - 460t = 75
16. Dividing both equations, we get:
T/t = 23/15
17. Now, substituting the value of T/t into the first equation, we get:
300(23/15) = 460
23/5 = 460/300
23/5 = 23/5
18. Therefore, the original speed of the car (S) is 23/5 times the time taken (t) to travel 100 km from
|
Explore Courses for Quant exam
|
|
Similar Quant Doubts
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer?
Question Description
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer?.
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free.
Here you can find the meaning of A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?a)60km/hrb)80km/hrc)100km/hrd)120km/hre)None of theseCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Quant tests.
|
|
Explore Courses for Quant exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup