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A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is the original speed of the Car?
  • a)
    20 km/hr
  • b)
    40 km/hr
  • c)
    60 km/hr
  • d)
    80 km/hr
  • e)
    Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A car started from Indore to Bhopal at a certain speed. The Car missed...
(x+40/s) + 5/4 = 40/s + 5x/4s — — — 1
(x+40/s) + 1 = 80/s + 5(x-40)/4s — — — 2
s = 40
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Most Upvoted Answer
A car started from Indore to Bhopal at a certain speed. The Car missed...
Problem Analysis:

- A car starts from Indore to Bhopal at a certain speed.
- The car misses an accident at 40 km away from Indore and reduces the speed to 4/5 of the original speed. Due to this, the driver reaches Bhopal by a late of 1 hr 15 min.
- If the car missed an accident at 80 km away from Indore and then maintained 4/5 of the original speed, then the driver would reach Bhopal by a late of 1 hour.
- We need to find the original speed of the car.

To solve this problem, we need to use the formula:

Time = Distance / Speed

Solution:

Let the original speed of the car be 'S'.

Let the distance between Indore and Bhopal be 'D'.

Case 1: The car misses an accident at 40 km away from Indore.

- The distance between the accident spot and Bhopal is (D - 40) km.
- The time taken to cover this distance at the reduced speed of 4S/5 is:
Time = (D - 40) / (4S/5) = (5/4) * (D - 40) / S

Case 2: The car misses an accident at 80 km away from Indore.

- The distance between the accident spot and Bhopal is (D - 80) km.
- The time taken to cover this distance at the reduced speed of 4S/5 is:
Time = (D - 80) / (4S/5) = (5/4) * (D - 80) / S

Given that the difference in time taken in both cases is 1 hr and 15 min (i.e., 1.25 hours).

(5/4) * (D - 40) / S - (5/4) * (D - 80) / S = 1.25

Simplifying and solving for 'S', we get:

S = 40 km/hr

Therefore, the original speed of the car is 40 km/hr.

Final Answer: Option B
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A car started from Indore to Bhopal at a certain speed. The Car missed an accident at 40Kms away from Indore, then the driver decided to reduce Car speed to 4/5 of the original speed. Due to this, he reached Bhopal by a late of 1hr 15min.Suppose if he missed an accident at 80Km away from Indore and from then he maintained 4/5 of original speed then he would reach Bhopal by a late of 1hour. Then what is theoriginal speed of the Car?a)20 km/hrb)40 km/hrc)60 km/hrd)80 km/hre)Cannot be determinedCorrect answer is option 'B'. Can you explain this answer?
Question Description
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