Quant Exam > Quant Questions > The distance of the School and house of Sures...
Start Learning for Free
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?
- a)28 kmph
- b)25 kmph
- c)20 kmph
- d)24 kmph
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The distance of the School and house of Suresh is 80km. One day he was...
80/x – 80/(x+4) = 1
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
Most Upvoted Answer
The distance of the School and house of Suresh is 80km. One day he was...
80/x – 80/(x+4) = 1
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
x(x+20) – 16(x+20) = 0
x = 16kmph
Increased speed = 20 kmph
Free Test
FREE
| Start Free Test |
Community Answer
The distance of the School and house of Suresh is 80km. One day he was...
Given:
Distance between School and house of Suresh = 80 km
Let, the normal speed of Suresh be x km/h
He was late by 1 hour, so he increased his speed by 4 km/h and reached college at normal time.
To find: The changed speed of Suresh
Concept Used:
Time = Distance/Speed
Calculation:
Let's assume that Suresh normally takes T hours to reach college.
So, according to the given data:
Time taken at normal speed = T hours
Time taken at increased speed = T - 1 hours
Using the concept of Time = Distance/Speed:
Time taken at normal speed = Distance/Normal speed
T = 80/x
Time taken at increased speed = Distance/Increased speed
T - 1 = 80/(x+4)
Now, we can solve these two equations to find the value of x.
80/x = 80/(x+4) + 1
80(x+4) = 80x + x(x+4)
80x + 320 = x^2 + 4x
x^2 - 76x - 320 = 0
(x-20)(x-56) = 0
As speed cannot be negative, we will take x = 20 km/h.
Now, to find the changed speed of Suresh, we need to add 4 km/h to his normal speed.
Therefore, the changed speed of Suresh = 20 + 4 = 24 km/h.
Hence, the correct answer is option (d) 24 kmph.
Distance between School and house of Suresh = 80 km
Let, the normal speed of Suresh be x km/h
He was late by 1 hour, so he increased his speed by 4 km/h and reached college at normal time.
To find: The changed speed of Suresh
Concept Used:
Time = Distance/Speed
Calculation:
Let's assume that Suresh normally takes T hours to reach college.
So, according to the given data:
Time taken at normal speed = T hours
Time taken at increased speed = T - 1 hours
Using the concept of Time = Distance/Speed:
Time taken at normal speed = Distance/Normal speed
T = 80/x
Time taken at increased speed = Distance/Increased speed
T - 1 = 80/(x+4)
Now, we can solve these two equations to find the value of x.
80/x = 80/(x+4) + 1
80(x+4) = 80x + x(x+4)
80x + 320 = x^2 + 4x
x^2 - 76x - 320 = 0
(x-20)(x-56) = 0
As speed cannot be negative, we will take x = 20 km/h.
Now, to find the changed speed of Suresh, we need to add 4 km/h to his normal speed.
Therefore, the changed speed of Suresh = 20 + 4 = 24 km/h.
Hence, the correct answer is option (d) 24 kmph.
|
Explore Courses for Quant exam
|
|
Similar Quant Doubts
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer?
Question Description
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer?.
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free.
Here you can find the meaning of The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The distance of the School and house of Suresh is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed speed of Suresh?a)28kmphb)25 kmphc)20kmphd)24kmphCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Quant tests.
|
|
Explore Courses for Quant exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup