A worker reaches his work place 15 minutes late by walking at 4 kmph f...
Given information:
A worker reaches his workplace 15 minutes late by walking at 4 kmph from his house.
The next day, he increases his speed by 2 kmph and reaches on time.
To find:
The distance from his house to his workplace.
Let's solve the problem step by step:
Step 1: Calculate the time taken to reach the workplace initially.
Given that the worker reaches his workplace 15 minutes late by walking at 4 kmph.
We know that speed = distance/time.
Let the distance from his house to his workplace be 'd' km.
So, the time taken to reach the workplace initially is (d/4) hours.
Step 2: Calculate the time taken to reach the workplace the next day.
The next day, the worker increases his speed by 2 kmph.
So, the speed becomes 4+2 = 6 kmph.
Now, he reaches on time.
Therefore, the time taken to reach the workplace the next day is (d/6) hours.
Step 3: Calculate the time difference.
Given that the worker reaches his workplace 15 minutes late initially.
15 minutes is equal to (15/60) = 0.25 hours.
So, the time taken to reach the workplace initially is (d/4) + 0.25 hours.
Step 4: Set up the equation.
Since the time taken to reach the workplace initially and the time taken the next day are equal:
(d/4) + 0.25 = d/6
Step 5: Solve the equation to find the distance.
Simplifying the equation:
6d + 1.5 = 4d
2d = 1.5
d = 1.5/2
d = 0.75
Therefore, the distance from his house to his workplace is 0.75 km.
Conclusion:
The distance from his house to his workplace is 0.75 km.