A person covers a certain distance at a he es 1 increases his speed by...
I think I know the explanation to this ques, but ur question is not clear
A person covers a certain distance at a he es 1 increases his speed by...
Given information:
- A person covers a certain distance at a speed.
- The person increases his speed by 25%.
- After increasing the speed, he takes minutes less to cover the same distance.
To find:
The time taken by the person initially to cover the distance at the original speed.
Assumptions:
- Let the distance covered be 'd'.
- Let the original speed be 's' units per minute.
- Let the time taken initially be 't' minutes.
Calculating the new speed:
- The person increases his speed by 25%, which means the new speed is 125% of the original speed.
- Mathematically, the new speed is calculated as follows: New speed = s + (25/100)s = s + 0.25s = 1.25s units per minute.
Calculating the new time:
- The person takes minutes less to cover the distance at the new speed.
- Let the new time taken be 't - x' minutes.
Calculating the new time using distance, speed, and time formula:
- Distance = Speed * Time
- For the original speed: d = s * t
- For the new speed: d = 1.25s * (t - x)
Solving the equations:
- From the above equations, we can equate the distances covered at the original and new speeds.
- s * t = 1.25s * (t - x)
- Dividing both sides by 's': t = 1.25(t - x)
- Expanding the equation: t = 1.25t - 1.25x
- Rearranging the terms: 1.25x = 0.25t
- Dividing both sides by 0.25: 5x = t
- Therefore, the initial time taken, t = 5x.
Calculating the value of x:
- It is given that the person takes minutes less to cover the distance at the new speed.
- Therefore, x = minutes.
Calculating the initial time:
- t = 5x
- t = 5 * 7
- t = 35
Final answer:
The time taken by the person initially to cover the distance at the original speed is 35 minutes.