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A particle of mass m moves wider the action of a central force whose potential energy is U(r) = kr6 , k > O. If the orbit be a circle of radius a about origin, then the total energy is ηka6. The value of η is _______.
    Correct answer is '4'. Can you explain this answer?
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    A particle of mass m moves wider the action of a central force whose p...

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    A particle of mass m moves wider the action of a central force whose p...
    The potential energy function provided is U(r) = kr^6, where k is a constant.

    To determine the force experienced by the particle, we need to calculate the negative gradient of the potential energy function. The force is given by the equation F = -∇U, where ∇ represents the gradient operator.

    Taking the derivative of U(r) with respect to r, we get:

    dU/dr = 6kr^5

    Now, we can calculate the force by taking the negative gradient:

    F = -∇U = -dU/dr = -6kr^5

    Therefore, the force experienced by the particle is F = -6kr^5.
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    A particle of mass m moves wider the action of a central force whose potential energy is U(r) = kr6, k > O. If the orbit be a circle of radius a about origin, then the total energy is ηka6. The value of ηis _______.Correct answer is '4'. Can you explain this answer?
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