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An energy-meter having a meter constant of 1200 rev per kWH is found to make 5 revolutions in 75 s. The load power is
- a)500 W
- b)100W
- c)200 W
- d)1000W
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
An energy-meter having a meter constant of 1200 rev per kWH is found t...
(c)
Number of revolutions = K × P × t
∴ 5=1200×P×(75/3600)
Number of revolutions = K × P × t
∴ 5=1200×P×(75/3600)
⇒ P = 200 W
Most Upvoted Answer
An energy-meter having a meter constant of 1200 rev per kWH is found t...
Solution:
Given that meter constant (K) = 1200 rev/kWh
Number of revolutions made by the energy meter = 5 rev
Time taken to make 5 revolutions = 75 s
Let us calculate the energy consumed by the load.
Energy consumed by the load = Number of revolutions / Meter constant
= (5 rev) / (1200 rev/kWh)
= (5/1200) kWh
Now, let us calculate the power consumed by the load.
Power = Energy / Time
= (5/1200) kWh / 75 s
= (5/1200) * 3600 / 75 W
= 0.2 kW
= 200 W
Therefore, the power consumed by the load is 200 W. Hence, option (C) is the correct answer.
Note: In this problem, we have used the formulae, Energy = Number of revolutions / Meter constant and Power = Energy / Time, to calculate the power consumed by the load. These formulae are commonly used in electrical energy measurement and billing.
Given that meter constant (K) = 1200 rev/kWh
Number of revolutions made by the energy meter = 5 rev
Time taken to make 5 revolutions = 75 s
Let us calculate the energy consumed by the load.
Energy consumed by the load = Number of revolutions / Meter constant
= (5 rev) / (1200 rev/kWh)
= (5/1200) kWh
Now, let us calculate the power consumed by the load.
Power = Energy / Time
= (5/1200) kWh / 75 s
= (5/1200) * 3600 / 75 W
= 0.2 kW
= 200 W
Therefore, the power consumed by the load is 200 W. Hence, option (C) is the correct answer.
Note: In this problem, we have used the formulae, Energy = Number of revolutions / Meter constant and Power = Energy / Time, to calculate the power consumed by the load. These formulae are commonly used in electrical energy measurement and billing.
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An energy-meter having a meter constant of 1200 rev per kWH is found to make 5 revolutions in 75 s. The load power isa)500 Wb)100Wc)200 Wd)1000WCorrect answer is option 'C'. Can you explain this answer?
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