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I. X² + 25X + 156 = 0
II. Y² + 29Y + 210 = 0
  • a)
    X > Y
  • b)
    X < Y
  • c)
    X ≥ Y
  • d)
    X ≤ Y
  • e)
    X = Y or relationship cannot be established
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
I. X² + 25X + 156 = 0II. Y² + 29Y + 210 = 0a)X > Yb)X <...
Given Quadratic Equations:
I. X² + 25X + 156 = 0
II. Y² + 29Y + 210 = 0

Comparing the Quadratic Equations:
To determine the relationship between X and Y, we can compare the coefficients of the quadratic equations.

Comparison of Coefficients:
1. For X² coefficient: 1 (in equation I) < 1="" (in="" equation="" />
2. For X coefficient: 25 (in equation I) < 29="" (in="" equation="" />
3. For constant term: 156 (in equation I) < 210="" (in="" equation="" />

Conclusion:
Since all the coefficients of equation II are greater than those of equation I, we can conclude that the roots of equation II (Y) are greater than the roots of equation I (X).
Therefore, the relationship between X and Y is X < y.="" hence,="" the="" correct="" answer="" is="" option="" 'a'="" -="" x="" /> Y.
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Community Answer
I. X² + 25X + 156 = 0II. Y² + 29Y + 210 = 0a)X > Yb)X <...
X= -12,- 13
Y = -14,- 15
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