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A sample of radioactive material has mass m, decay constant λ, and molecular weight M. Avogadro number = NA. The initial activity of the sample is
- a)λm
- b)λm/M
- c)λm NA/M
- d)mNAeλ
Correct answer is option 'C'. Can you explain this answer?
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A sample of radioactive material has mass m, decay constant λ, ...
Λ, and half-life T. The rate of decay, R, of the radioactive material is given by the equation:
R = λm
where R is the rate of decay, λ is the decay constant, and m is the mass of the radioactive material.
The half-life, T, is the time it takes for half of the radioactive material to decay. It can be calculated using the equation:
T = ln(2) / λ
where T is the half-life and λ is the decay constant.
Let's say we have a sample of radioactive material with a mass of 10 grams and a decay constant of 0.05 per second. We can calculate the rate of decay and the half-life using the equations above.
Using the equation R = λm, we can substitute the given values:
R = (0.05 per second) * (10 grams)
R = 0.5 grams per second
So, the rate of decay for this sample of radioactive material is 0.5 grams per second.
Using the equation T = ln(2) / λ, we can substitute the given values:
T = ln(2) / 0.05 per second
T ≈ 13.86 seconds
So, the half-life of this sample of radioactive material is approximately 13.86 seconds.
R = λm
where R is the rate of decay, λ is the decay constant, and m is the mass of the radioactive material.
The half-life, T, is the time it takes for half of the radioactive material to decay. It can be calculated using the equation:
T = ln(2) / λ
where T is the half-life and λ is the decay constant.
Let's say we have a sample of radioactive material with a mass of 10 grams and a decay constant of 0.05 per second. We can calculate the rate of decay and the half-life using the equations above.
Using the equation R = λm, we can substitute the given values:
R = (0.05 per second) * (10 grams)
R = 0.5 grams per second
So, the rate of decay for this sample of radioactive material is 0.5 grams per second.
Using the equation T = ln(2) / λ, we can substitute the given values:
T = ln(2) / 0.05 per second
T ≈ 13.86 seconds
So, the half-life of this sample of radioactive material is approximately 13.86 seconds.
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A sample of radioactive material has mass m, decay constant λ, and molecular weight M. Avogadro number = NA. The initial activity of the sample isa)λmb)λm/Mc)λm NA/Md)mNAeλCorrect answer is option 'C'. Can you explain this answer?
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