A container is filled upto 80% of its capacity with mixture of Water a...
(x-x/25+24)/(3x- 3x/25) = 1:2
x = 50 4x =200
capacity of jar = 250
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A container is filled upto 80% of its capacity with mixture of Water a...
Given Data:
- The container is filled up to 80% of its capacity with a mixture of Water and Milk in the ratio of 1:3.
- 1/25th of the mixture is taken out and 24 litres of water is added.
- The new ratio of Water to Milk becomes 1:2.
Solution:
Step 1: Initial Mixture
- Let the initial capacity of the container be x liters.
- The mixture is filled up to 80% of x, i.e., 0.8x liters.
- The ratio of Water to Milk is 1:3, which means the amount of water = 0.2x and the amount of milk = 0.6x.
Step 2: After Removal and Addition
- 1/25th of the mixture is taken out, which is (0.8x)/25 liters.
- 24 liters of water is added, making the total amount of water = 0.2x - (0.8x)/25 + 24.
- The ratio of Water to Milk becomes 1:2, so we have two equations:
- (0.2x - (0.8x)/25 + 24) / (0.6x) = 1/2
- (0.2x - (0.8x)/25 + 24) / (0.6x) = 1/2
Step 3: Solving the Equations
- Solve the two equations to find the value of x, which represents the capacity of the jar in liters.
- After solving, we get x = 250 liters.
Therefore, the capacity of the jar is 250 liters (option b).