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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)
- a)0.1 M
- b)0.001 M
- c)0.01 M
- d)10−4 M
Correct answer is option 'B'. Can you explain this answer?
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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . ...
10ml of this solution is diluted to 1000ml N1V1 = N2 V2
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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . ...
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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . ...
First, we need to calculate the number of moles of Na2CO3 in the 250 ml solution.
Number of moles = mass / molar mass
Number of moles = 2.65 g / 106 g/mol
Number of moles = 0.025 moles
Next, we need to calculate the concentration of the resultant solution after dilution.
Concentration = moles / volume
Concentration = 0.025 moles / 1 L
Concentration = 0.025 M
So, the concentration of the resultant solution is 0.025 M, which is equivalent to 0.01 M. Therefore, the correct answer is option c) 0.01 M.
Number of moles = mass / molar mass
Number of moles = 2.65 g / 106 g/mol
Number of moles = 0.025 moles
Next, we need to calculate the concentration of the resultant solution after dilution.
Concentration = moles / volume
Concentration = 0.025 moles / 1 L
Concentration = 0.025 M
So, the concentration of the resultant solution is 0.025 M, which is equivalent to 0.01 M. Therefore, the correct answer is option c) 0.01 M.
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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer?
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250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer?.
250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 =106)a)0.1 Mb)0.001 M c)0.01 M d)10−4 MCorrect answer is option 'B'. Can you explain this answer?.
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