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The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is
- a)50 %
- b)43 %
- c)55.3 %
- d)72.24%
Correct answer is option 'D'. Can you explain this answer?
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The values of electronegativity of atoms A and B are 1.20 and 4.0 resp...
We know that ionic characters = 16[EA− EB] + 3.5 × [EA − EB]2
or ionic characters = 72.24%
or ionic characters = 72.24%
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The values of electronegativity of atoms A and B are 1.20 and 4.0 resp...
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The values of electronegativity of atoms A and B are 1.20 and 4.0 resp...
To find the percentage of ionic character of atom A, we can use the equation:
Percentage of ionic character = (1 - e^2 / (4 * d))^2 * 100
Where e is the difference in electronegativity between atoms A and B (4.0 - 1.20 = 2.80) and d is the internuclear distance.
However, without knowing the internuclear distance, we cannot calculate the percentage of ionic character accurately. The internuclear distance plays a crucial role in determining the extent of ionic character in a bond.
Therefore, without additional information, we cannot determine the percentage of ionic character of atom A.
Percentage of ionic character = (1 - e^2 / (4 * d))^2 * 100
Where e is the difference in electronegativity between atoms A and B (4.0 - 1.20 = 2.80) and d is the internuclear distance.
However, without knowing the internuclear distance, we cannot calculate the percentage of ionic character accurately. The internuclear distance plays a crucial role in determining the extent of ionic character in a bond.
Therefore, without additional information, we cannot determine the percentage of ionic character of atom A.
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The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is a)50 %b)43 %c)55.3 % d)72.24%Correct answer is option 'D'. Can you explain this answer?
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The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is a)50 %b)43 %c)55.3 % d)72.24%Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is a)50 %b)43 %c)55.3 % d)72.24%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A – B bond is a)50 %b)43 %c)55.3 % d)72.24%Correct answer is option 'D'. Can you explain this answer?.
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